6.02 × 10^4 ÷ 5.1 × 10^6
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The magnitude of the tangential acceleration of the hanging mass is 2mg/MR
<h3>Tangential acceleration of the hanging mass</h3>The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;
τ = Iα
Where;
- I is the moment of inertia
- α is the angular velocity
Where;
- m is the hanging mass
- M is the mass of solid disk
The tangential acceleration is calculated as follows;
Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR
Learn more about tangential acceleration here: brainly.com/question/11476496
<h2>Answer</h2>
The answer is 29495.3 kg
<h2>Explanation</h2>As we know, the Newton's Second Law of Motion
The F exerted by catapult = 9.35 *
The Time is = 2.10 s
Velocity of the catapult = 240 km/h = 66.6 m/s (240*1000 m /3600 s)
The mass of jet = ?
First detrmine the acceleration as
{/tex}Acceleration = Velocity/Time {/tex}
Rearrange the formaula as
The mass will be 29495.3 kg