The empirical formula of a compound is CH3- The molecular formula of this compound could be C2H6 CH4 C3H6 C2H4

If electromagnetic radiation has a frequency of 2.0×1015s−1, what is the radiation’s energy?(1 point)

Alika [10]

Frequency=v=2×10^15Hz
Energy=E

Using planks quantum theory

$\\ \sf\longmapsto E=hv$

$\\ \sf\longmapsto E=6.626\times 10^{-34}Js\times 2\times 10^{15}s^{-1}$

$\\ \sf\longmapsto E=13.252\times 10^{-19}J$

$\\ \sf\longmapsto E=1.3\times 10^{-18}J$

7 0

3 years ago

5.82 760. Х 425.976 answer should have sig.figs. calculated answer:

Mekhanik [1.2K]

Answer:

2482.4177376

Explanation:

1: 5.82 760 times 425.976

2: You will find the answer that is 2482.4177376

Hope this helps.

7 0

3 years ago

A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo

Liula [17]

Answer: The molar mass of the insulin is 6087.2 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = $62.364\text{ L.mmHg }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol$

Hence, the molar mass of the insulin is 6087.2 g/mol

8 0

3 years ago

Predict what the Co, levels will be when you are "old". How many plants/trees need to be planted now to keep carbon dioxide in t

Anna [14]

Answer:

A lot of them.

Explanation:

It would take hundreds of thousands of trees to clear all of the emmisions.

5 0

3 years ago

Use Boyle's Law to explain what would happen to the volume of a helium- filled balloon if it was carried underwater by a diver t

oksano4ka [1.4K]

The deeper the diver takes the helium balloon, the more it reduces in size. This is due to the pressure of the water column above pressing on the balloon. According to Boyle’s law (P= k*1/V.), as the volume of the balloon decreases, the pressure of the helium inside increases.

4 0

3 years ago