Answer:
Explanation:
capacitance of capacitor
= ε₀ A / d , A is area of plate , d is plate separation
= (8.85 x10⁻¹² x 1.7² x 10⁻⁴) /( .35 x 10⁻³ )
= 73 x 10⁻¹³ F
Charge = 4.5 x 10⁻⁷
voltage between the plates,
Δ V = charge / capacitance
= 4.5 x 10⁻⁷ / 73 x 10⁻¹³
= .0616 x 10⁶
= 616 x 10² V
To make the vottage double , we will reduce capacitance to half .
To reduce capacitance half we will increase plate distance to double.
new plate distance
= 1.7 x 2
= 3.4 cm
Answer:
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# CARRY ON LEARNING
Because an object in rest stays in rest until an unequal force pushes it so gravity is pushing on the egg making it drop
Answer:
a. The electric field lines are linear and perpendicular to the plates inside a parallel-plate capacitor, and always from positive plate to the negative plate. If a positive charge is released near the positive plate, then it will follow a linear path towards the negative plate under the influence of electrostatic force, F = Eq, where q is the charge of the particle. The electric field inside a parallel plate capacitor is constant and equal to
This can be calculated by Gauss' Law.
A positive charge always follow the electric field lines when released. Another approach is that the positive plate repels the positive charge and negative plate attracts the positive charge. Therefore, the positive charge follows a path towards the negative charge.
b. The particle moves from the higher potential to the lower potential. The direction of motion is the same as the direction of the force that moves the particle, so the work done on the particle by that force is positive.
Answer:
the tension of the rope is 34.95 N
Explanation:
Given;
length of the rope, L = 3 m
mass of the rope, m = 0.105 kg
frequency of the wave, f = 40 Hz
wavelength of the wave, λ = 0.79 m
Let the tension of the rope = T
The speed of the wave is given as;
Therefore, the tension of the rope is 34.95 N