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2 years ago

How long does it take the projectile to reach its highest point in its trajectory?

Physics

1 answer:

NeTakaya2 years ago

3 0

Answer:

It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance).

Explanation:

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5 milligrams into quintal

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Answer:

divide the mass value by 1e+8

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2 years ago

A catapult used by medieval armies hurls a stone of mass 32.0 kg with a velocity of 50.0 m/s at a 30.0 degree angle above the ho

NISA [10]

Answer:

The horizontal distance traveled when the stone returns to its original height = 220.81 m

Explanation:

Considering vertical motion of catapult:-

At maximum height,

Initial velocity, u = 50 sin30 = 25 m/s

Acceleration , a = -9.81 m/s²

Final velocity, v = 0 m/s

We have equation of motion v = u + at

Substituting

v = u + at

0 = 25 - 9.81 x t

t = 2.55 s

Time of flight = 2 x Time to reach maximum height = 2 x 2.55 = 3.1 s

Considering horizontal motion of catapult:-

Initial velocity, u = 50 cos30 = 43.30 m/s

Acceleration , a = 0 m/s²

Time, t = 5.10 s

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

s = 43.30 x 5.10 + 0.5 x 0 x 5.10²

s = 220.81 m

The horizontal distance traveled when the stone returns to its original height = 220.81 m

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2 years ago

. A student times a car traveling a distance of 2 m. She finds that it takes the car 5 s to

AveGali [126]

No, the car travels 1 metre in 5s at the start which is 0.2m/s, while the second meter it travels one metre in 8 seconds which is 0.125 m/s, the speed changes therefore it is not constant during the two metres the car travels

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2 years ago

Too much skepticism can

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Too much skepticism will lead one to doubt everything while too little will lead to gullibility.

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2 years ago

Read 2 more answers

How far from a 10 µC point charge will the potential be 1000 V?

Drupady [299]

<h2>Answer:</h2>

• Point charge (Q) = 10 μC = 10 × 10⁻⁶ C

• Potential (V) = 1000 V

• Distance (r) = ?

$\implies V = \dfrac{KQ}{r} \\$

$\implies r= \dfrac{KQ}{V}$

$\implies r= \dfrac{9 \times {10}^{9} \times 10 \times {10}^{ - 6} }{1000} \\$

$\implies r= \dfrac{90 \times {10}^{3} }{1000} \\$

$\implies r= \dfrac{90 \times {10}^{3} }{ {10}^{3} } \\$

$\implies r= 90 \times {10}^{3} \times {10}^{ - 3} \\$

$\implies\bf r= 90\:m \\$

Hence,the option B) 90 m is the correct answer.

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2 years ago

How long does it take the projectile to reach its highest point in its trajectory?​

How long does it take the projectile to reach its highest point in its trajectory?