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Lubov Fominskaja [6]
3 years ago
15

It is said that people often behave in unusual ways during a full moon. a)

Physics
1 answer:
timurjin [86]3 years ago
4 0

Answer: baby moon gravity

Sorry I dont know how to do it :/

Explanation:

moon + gravity = baby moon gravity

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The air speed of a plane is defined as its velocity with respect to the surrounding air, or in other words how fast the plane wo
amid [387]

Answer:

3

Explanation:

because

7 0
3 years ago
Which type of heat transfer causes your face to feel warm when you sit in the sun?
MA_775_DIABLO [31]

Answer:

Radiation

Explanation:

The sun radiates energy to the earth to make it warmer near the equator.

6 0
4 years ago
Napoleon’s cannon, having a muzzle velocity of 333 m/s, is fired at a 0 degree angle off a cliff. The ball lands 622 m away from
timama [110]

The cannon is 17.69 m above the ground level

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Horizontal speed (u) = 333 m/s
  • Horizontal distance (s) = 622 m
  • Height (h) =?

<h3>How to determine the time </h3>

We'll begin by calculating the time taken for the ball to land on the ground. This can be obtained as follow:

  • Horizontal speed (u) = 333 m/s
  • Horizontal distance (s) = 622 m
  • Time (t) =?

s = ut

622 = 333 × t

Divide both sides by 333

t = 622 / 333

t = 1.9 s

<h3>How to determine the height</h3>

The height of the cannon above the ground can be obtained as illustrated below:

  • Acceleration due to gravity (g) = 9.8 m/s²
  • Time (t) = 1.9 s
  • Height (h) =?

h = ½gt²

h = ½ × 9.8 × 1.9²

h = 4.9 × 3.62

h = 17.69 m

Learn more about motion under gravity:

brainly.com/question/20385439

#SPJ1

3 0
1 year ago
When light reaches the end of a barrier on the edge of an opening it diffracts, which means...
Mama L [17]
Hey there Evan!

Let's remember, these are (light waves). So, we you learn about waves, you would remember that when light does reach an end, they will most likely just (bounce back). That's all it would actually do.

I Hope this helps you!
3 0
3 years ago
A single conservative force F = (7.0x - 11) N, where x is in meters, acts on a particle moving along an x axis. The potential en
Umnica [9.8K]

Answer:

(a) 34.6429J

(b) -1.57 m

(c) 4.71 m

Explanation:

The derivative of the potential energy with respect to the position is equal to the negative of the force, so:

-\frac{dU}{dx}=F\\ dU=-Fdx

Then, if we integer both sides, we get:

∫dU = -∫(7x - 11)dx

U=\frac{-7}{2}x^{2} + 11x + c

we know that U is equal to 26 J when x is zero, so:

U=\frac{-7}{2}x^{2} + 11x + c

26=\frac{-7}{2}(0)^{2} + 11(0) + c

26=c

Finally, the equation for the potential energy is:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

Therefore, the maximum positive potential energy is the energy when x is equal to 11/7. That is because the equation of U is the equation of a parable, and the vertex in a parable is given by:

x=\frac{-b}{2a} = \frac{-11}{2(-7/2)} =\frac{11}{7}

Where b is the number beside x and a is the number beside x^{2}, Then, the value of maximum U is:

U(11/7)=\frac{-7}{2}(11/7)^{2} + 11(11/7) + 26

U(11/7)=34.6429J

On the other hand, the negative and positive values of x where the potential energy is equal to zero is calculated as:

U(x)=\frac{-7}{2}x^{2} + 11x + 26

0=\frac{-7}{2}x^{2} + 11x + 26

if we solve this using the quadratic equation, we get:

x =\frac{-11+\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=-1.5747

x =\frac{-11-\sqrt{11^{2}-4(-7/2)(26)} }{2(-7/2)}=4.7175

Finally, the negative and positive values of x where the potential energy is equal to zero are -1.5747 and 4.7175 respectively.

3 0
3 years ago
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