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Hunter-Best [27]
3 years ago
12

Please help me, I beg you​

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

40g

Explanation:

Solubility of Copper sulfate at 90°=60g

Solubility of potassium bromide at 90°=100g

100g-60g=40g

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You rubbed two identical balloons in your hair's friend. This causes the balloons to become charged negatively with a magnitude
dem82 [27]

Answer:

a)  F = 2.25 10³ N, b) REPULSIVE.

Explanation:

a) The electric force is given by coulomb's law

           F = k \frac{q_1q_2}{r^2}k q1q2 / r2

in this case nso indicate that the two charges have the same value

           q₁ = q₂ = 2.5 10⁻⁶ C

Let's reduce the magnitudes to the SI system

           r = 0.5 cm (1m / 100cm) = 5 10⁻³ m

let's calculate

           F = 9 \ 10^9 \frac{(2.5 \ 10^{-6})^2 }{(5 \ 10^{-3})^2}

           F = 2.25 10³ N

b) In electricity, electric charges of the same sign repel and those of the opposite sign attract

In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.

7 0
3 years ago
Physics help pleaseee
Ilia_Sergeevich [38]

Answer:

the first questions answer is- the pressure is the same (balanced) outside and inside the window.

the second questions answer is- the atmospheric pressure increases.

Explanation:

I hope that this is what you were looking for.

6 0
3 years ago
An automobile whose speed is increasing at a rate of 0.800 m/s2 travels along a circular road of radius 10.0 m.
Ket [755]

(a) a_t = 0.800 m/s^2

The tangential acceleration component of the car is simply equal to the change of the tangential speed divided by the time taken:

a_t = \frac{\Delta v}{\Delta t}

This rate of change is already given by the problem, 0.800 m/s^2, so the tangential acceleration of the car is

a_t = 0.800 m/s^2

(b) a_c = 0.9 m/s^2

The centripetal acceleration component is given by

a_c = \frac{v^2}{r}

where

v is the tangential speed

r is the radius of the trajectory

When the speed is v = 3.00 m/s, the centripetal acceleration is (the radius is r = 10.0 m):

a_c = \frac{(3.00 m/s)^2}{10.0 m}=0.9 m/s^2

(c) 1.2 m/s^2, 48.4^{\circ}

The centripetal acceleration and the tangential acceleration are perpendicular to each other, so the magnitude of the total acceleration can be found by using Pythagorean's theorem:

a=\sqrt{a_t^2+a_c^2}=\sqrt{(0.8 m/s^2)^2+(0.9 m/s^2)^2}=1.2 m/s^2

and the direction is given by:

tan \theta =\frac{a_c}{a_t}=\frac{0.9 m/s^2}{0.8 m/s^2}=1.125\\\theta=tan^{-1}(1.125)=48.4^{\circ}

where the angle is measured with respect to the direction of the tangential acceleration.

4 0
3 years ago
Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) With what initial velo
alukav5142 [94]

Answer:

v_i=189.315ft/s

Explanation:

We are going to use the accelerated motion formula v_f^2=v_i^2+2ad on the vertical component taking the upwards direction as positive.

Since <em>at maximum height the speed will be v_f=0m/s</em>, the formula can be written as v_i=\sqrt{-2ad}, which for our values is:

v_i=\sqrt{-2(-32ft/s^2)(560ft)}=189.314553059ft/s=189.315ft/s

Written to three decimal places.

3 0
4 years ago
Which of the following best defines force
nataly862011 [7]

Answer:

force is a push or a pull

8 0
4 years ago
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