To solve this problem we will apply the concepts related to the Voltage depending on the Electric field and the distance where it is applied. The relationship of this relationship is given in the following form:
Here,
E = Electric Field
V = Voltage
d = Distance
Our values are given as,
Replacing at the first equation we have,
Therefore the electric field in the strip is 2.866V/m
The equation for work (W) done by an electric field is:
W = qΔV
where q is the magnitude of the charge and ΔV is the potential difference. The question gives you W and q, so plug n' play to find ΔV:
10 = 2ΔV
ΔV = 5
The distance is 9.0 meters because that's how far the person ran. The displacement is 2.4 meters North because displacement is a speed AND direction. Basically you're calculating how far you are from where you started.
2.5 cm 1 meter 1 Year
_______ x ________ x ________ = 0.002 m/month
Year 100 cm 12 mo.s
Answer:
C. 450v
Explanation:
Using
Voltage= B*distance of separation*velocity
3mm x 0.3T x 5E5m/s
= 450v
