The two forms of oxygen, O2 and O3 is "<span>They have different molecular structures and different properties."</span>
Answer:
(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)
Explanation:
Data Give:
Reaction between ammonium phosphate solution and solution of aluminum nitrate
- Write a balanced chemical equation
Details:
To write a balanced chemical equation we have to know formula units of compounds or molecules
Formula units
ammonium phosphate : (NH₄)₃PO₄
aluminum nitrate: Al(NO₃)₃
ammonium nitrate: NH₄NO₃
Now to write a chemical equation
- we have to write the chemical formulas or formula unit of each compound
- write the reactant on left side of the arrow
- write the product on the right side of the arrow
- put a plus sign in 2 reactants and products on each side of the arrow
- balance the equation by putting coefficient with compound formula
- write the phase symbols on the right corner of the compound formula in brackets
So the Reaction will be
(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + NH₄NO₃
Now balance the Chemical equation
(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + 3NH₄NO₃
Now write the phase Symbols
(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)
all compounds in the reaction are in liquid form and soluble in water
*** Note:
There is no aluminum nitrite in chemicals formulas
Also ammonium nitrite can not be used in pure isolated form due to its highly instability
Answer:
True
Explanation:because of the motion
Answer:
The solubility product of zinc sulfide is 
.
Explanation:
Solubility of the zinc sulfide = 
S S
The expression of solubility product is given by :
![K_{sp}=[Zn^{2+}]\times [S^{2-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BZn%5E%7B2%2B%7D%5D%5Ctimes%20%5BS%5E%7B2-%7D%5D)
The solubility product of zinc sulfide is .
Answer:
1.6mole of H2O
Explanation:
First let us generate a balanced equation for the reaction. This is illustrated below:
2H2 + O2 —> 2H2O
Molar Mass of O2 = 2 x 16 = 32g/mol.
Mass of O2 = 25.6g
Number of mole of O2 = Mass /Molar Mass
Number of mole of O2 = 25.6/32
Number of mole O2 = 0.8mol
From the equation,
1mole of O2 produced 2moles H2O.
Therefore, 0.8mol of O2 will produce = 0.8 x 2 = 1.6mole of H2O
