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AfilCa [17]
2 years ago
7

How to know if you can heat a laboratory flask and other glassware?

Chemistry
1 answer:
AnnyKZ [126]2 years ago
7 0

Answer:

fill the flask with water. apply heat, when you see the vapor you will know is heat

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What is the percent magnesium in a sample made of 24g Mg and 70gCl?
seropon [69]

Answer:

Total percent of magnesium in sample = 25.5%

Explanation:

Given:

Mass of magnesium = 24 gram

Mass of chlorine = 70 gram

Find:

Total percent of magnesium in sample = ?

Computation:

Total mass of sample = Mass of magnesium + Mass of chlorine

Total mass of sample = 24 gram + 70 gram

Total mass of sample = 94 gram

Total percent of magnesium in sample = [Mass of magnesium / Total mass of sample]100

Total percent of magnesium in sample = [24/94]100

Total percent of magnesium in sample = [0.255]100

Total percent of magnesium in sample = 25.5%

5 0
3 years ago
Use the following equation to answer the questions below.
sertanlavr [38]

Answer:

Explanation:

Here is ur answer what you wanna do first is calculate the first and second numbers and letters this should be ur answer = -394 + 2 x (-242) - (-75) + 2 x 0 = -803 kJ/mol

4 0
2 years ago
When The appearance of a system changes does the mass of the system also change why why not
seropon [69]
No, because the appearance has nothing to do with system as well as the fact that appearance is only how it looks

(Btw, that toga picture is like... ughhhh!) hope this helps you ♥︎☀︎☁︎♨︎

5 0
3 years ago
Read 2 more answers
Select the correct answer.
muminat

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

Molar mass of Ag_2S = 2(107.87)+32.06  = 247.8 g per mol

The dimensional set up for the complete problem is:

0.0150L(\frac{2.50molAgNO_3}{1L})(\frac{1molAg_2S}{2molAgNO_3})(\frac{247.8gAg_2S}{1molAg_2S})

= 4.65gAg_2S

So, the correct choice is B. 4.65 g.


7 0
3 years ago
4. Which elements would have similar properties to potassium?
iren [92.7K]

Answer:

The answer is A. Lithium and Sodium

5 0
2 years ago
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