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vredina [299]
3 years ago
4

Which statement describes a homogeneous catalyst?

Chemistry
2 answers:
wlad13 [49]3 years ago
7 0
A homogeneous catalyst is in the same phase as the reactants.
dedylja [7]3 years ago
6 0

Answer:

B

Explanation:

Answer on the Unit Test on Edge 2021

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C. NO2 is covalent. Hope this helps!
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How many seconds are in one millisecond?
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Explanation:

I thought it was B, but i was wrong... TwT, so now you know not to choose that one, but i belive the right answer was D.

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3 years ago
A block of aluminum weighing 200 g is cooled from 100C to 50°C with the release of 1080 joules of heat. From this data, calculat
babunello [35]

Answer:

0.108

Explanation:

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M is mass

Q is th heat release

C is specific heat

O is the temperature change

Substitute what you have and what you get in the information in the equation then you will get your answers

6 0
3 years ago
The world's total petroleum reserve is estimated at 2.0 x 10^22 joules La joule (J) is the unit of energy where 1J =1kg m^2/s^2)
mamaluj [8]

Answer:

It will take 1.1\times 10^{2}years to exhaust the supply

Explanation:

We have to apply unitary method to solve this problem.

Divide total petroleum reserve by petroleum consumption in each year to calculate estimated time.

Presently, 1.8\times 10^{20} joules of petroleum are being consumed per year.

Hence, applying unitary method, 2.0\times 10^{22} joules of petroleum can be consumed in \frac{2.0\times 10^{22}}{1.8\times 10^{20}}years=1.1\times 10^{2}years

3 0
3 years ago
The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
astraxan [27]

Answer:

It will take 6.6 hours for 75% of the lead to decay.

Explanation:

The radioactive decay follows first order rate law

The half life and rate constant are related as

k=rate constant=\frac{0.693}{halflife}=\frac{0.693}{3.3}=0.21h^{-1}

The rate law for first order reaction is

time=\frac{1}{k}(ln[\frac{A_{0}}{A_{t}}]

Where

A0 = initial concentration = 1 g

At= final concentration = 0.25 g (as 75% undergoes decay so 25% left]

time=\frac{1}{0.21}(ln(\frac{1}{0.25})=6.6hours

5 0
3 years ago
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