Question

Sheldon spins the two spinners below one time what are the chance he will spin 3 or c ?

Answer 1

Answer:

$P(3\ or\ c) = 0.45$

Step-by-step explanation:

Given

See attachment for spinner

Required

$P(3\ or\ c)$

From the first spinner, we have:

$S = \{1,2,3,4,5\}$ --- Sample Space

$n(S)=5$

So, P(3) is:

$P(3) = \frac{n(3)}{n(S)}$

$P(3) = \frac{1}{5}$

$P(3) = 0.20$

From the second spinner, we have:

$S = \{a,b,c,d\}$

$n(S) = 4$

So, P(c) is:

$P(c) = \frac{n(c)}{n(S)}$

$P(c) = \frac{1}{4}$

$P(c) = 0.25$

The required probability is then calculated as:

$P(3\ or\ c) = P(3) + P(c)$

$P(3\ or\ c) = 0.20 + 0.25$

$P(3\ or\ c) = 0.45$