Answer:
- 75-{(8×3)+6}
- 75-{24+6}
- 75-30
- 45
hope it helps
<h3>stay safe healthy and happy.</h3>
I would recommend "Introduction to Linear Algebra," by Gilbert Strang. It is a compact but very helpful textbook reference written by a well-known MIT professor. There is a corresponding online MIT course that is free, so that's a bonus. I am currently using it to study linear algebra with no class or previous experience, and I think it does a solid job of explaining things. Each section in the book has a set of questions for you to work through, and answers to selected questions appear in an appendix at the end of the book.
Hope this helps!
To do this, we first want to see how many participants there are in total by adding both males and females.

Now we know that there were 220 total participants, but only 121 were females.
This allows us to set up the fraction 121/220= the percent female.

or 55%
Answer:
2.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
3
,
5
)
Equation Form:
x
=
3
,
y
=
5
3.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
2
,
8
)
4.Solve for the first variable in one of the equations, then substitute the result into the other equation.
Point Form:
(
2
,
−
3
)
Step-by-step explanation:
Answer:
C. The distribution for town A is symmetric, but the distribution for
town B is negatively skewed.
Step-by-step Explanation:
From the box plots attached in the diagram below, which shows data of low temperatures for town A and town B for some days, we can compare the shapes of the box plot by visually analysing both box plots and how the data for each town is distributed.
=> For town A, the shape of the box plot is symmetric because both quartiles seem equal, and the median also divides the rectangular box into two equal halves. Both whiskers also appear to be of equal lengths.
The box plot for Town A takes a symmetric shape, and this shows a typical normal distribution of data.
=> On the other hand, Town B data distribution is different. The median seem close to the top half of the box and does not divide the box into equal halves. This shows the distribution is skewed. Since the whisker is shorter from the upper end of the box to the left side, we can infer that the distribution for Town B is skewed to the left, and it is negatively skewed.
=> The right comparison of the shapes of the box plots is "C. The distribution for town A is symmetric, but the distribution for town B is negatively skewed."