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3 years ago

Harold took five different samples of thirty-five randomly selected students from the 520 students he surveyed. The

Mathematics

1 answer:

mars1129 [50]3 years ago

3 0

Answer:

Step-by-step explanation:

just took the test! gl

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The possible values of x are given by x−3≥2 . What is the least possible value of 5x ?

mamaluj [8]

The answer would be twenty five because $x-3 \geq 2
$ equals $x \geq 5$ leaving you with x = 5 at a minimum. So 5x: 5 x 5 = 25

Hope this helps! :)

5 0

3 years ago

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m

photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures = 0.025 per hour.

Then for 8 hours , the mean of failures = $\lambda=8\times0.25=2$ per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}$

Now, the probability that the instrument does not fail in an 8-hour shift :-

$P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353$

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0

3 years ago

PLSSSSS HELP I HAVE BEEN STUCK ON THIS FOR THE PAST HOUR!!!!!!!!!!!!!!!!!!!!!!!!!

vladimir1956 [14]

Answer:

$- 6 \sqrt{2}$

Step-by-step explanation:

simplify

$\sqrt{28800}$

$120 \sqrt{2}$

then

-0.05 × 120 = -6

then we have our answer

-6√2

6 0

3 years ago

sume of angles of a triangel greater than 180 degrees when teh triange is so large that it extends to cosmological scales

Vesna [10]

In hyperbolic geometry, the angle sum of a triangle is always less than 180 degrees.

A lune is a wedge of a sphere with angle θ, represented by L(θ) in the proof.

α, β, and γ are the three angles of the triangle.

4πr²+4area[αβγ]=2L(α)+2L(β)+2L(γ)

2(2πr²+2area[αβγ])=2(L(α)+L(β)+L(γ))

2πr²+2area[αβγ]=L(α)+L(β)+L(γ)

At this point, we need to use a theorem that states that a lune whose corner angle is θ radians has an area of 2θr².

2πr²+2area[αβγ]=2αr²+2βr²+2γr²

2πr²+2area[αβγ]=2r²(α+β+γ)

π+area[αβγ]r²=α+β+γ

At this point, it is clear that the sum of the angles is equal to π plus the area[αβγ]r² (which cannot be zero).

To learn more about triangles and geometry,

brainly.com/question/2773823

#SPJ4

5 0

1 year ago

What is the average rate of change from -3 to 0 of the function represented by the graph?

lbvjy [14]

Average rate of change = change in y ÷ change in x

We already know the change in x because we are measuring the x values from -3 to 0.

change in x = 0-(-3) = 3

To find the change in y find the difference between the corresponding y-values when x=0 and when x=-3.

change in y = 0.5-2 = -1.5

average rate of change = -1.5/3 = -0.5

answer: -0.5

3 0

3 years ago