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3 years ago

‼️ PLEASEE HELPPP ‼️

Mathematics

1 answer:

Naddik [55]3 years ago

4 0

Answer:

Step-by-step explanation:

3x - 27 = x +11

3x -27 +27 = 11 + 27

3x - x = x -x + 38

2x = 38

2x ÷ 2 = 38

X = 19

19 × 3 -27 = 30

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What property is 5(x+y)=5x+5y

Law Incorporation [45]

Answer: Distributive Property

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3 years ago

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago

Does anybody know the answer to these questions?

san4es73 [151]

Answer:

1. 625,000 J

2. 100 J

4. 5 kg

5. √5 ≈ 2.236 m/s

Step-by-step explanation:

You should be aware that the SI derived units of Joules are equivalent to kg·m²/s².

To reduce confusion between m for mass and m for meters, we'll use an italic m for mass.

In each case, the "find" variable is what's left after we put the numbers into the formula. It is what the question is asking for. The "given" values are the ones in the problem statement and are the values we put into the formula. The formula is the same in every case.

1. KE = (1/2)mv² = (1/2)(2000 kg)(25 m/s)² = 625,000 kg·m²/s² = 625,000 J

2. KE = (1/2)mv² = (1/2)(0.5 kg)(20 m/s)² = 100 kg·m²/s² = 100 J

4. KE = (1/2)mv²

250 J = (1/2)m(10 m/s)² = 50 m²/s²

(250 kg·m²/s²)/(50 m²/s²) = m = 5 kg

5. KE = (1/2)mv²

2000 kg·m²/s² = (1/2)(800 kg)v²

(2000 kg·m²/s²)/(400 kg) = v² = 5 m²/s²

v = √5 m/s ≈ 2.236 m/s

7 0

3 years ago

In a pen with rabbits and chickens someone counted 25 heads and 80 legs a rabbit has four legs and each chicken has 2 legs, how

Komok [63]

I just kind of sat here playing with numbers i dont really know a shortcut but the answer is 10 chickens and 15 rabbits
10*2= 20 each chicken has two legs so thats 10 heads 20 legs
15*4=60 each rabbit has four legs so thats 15 heads 60 legs
15+10=25 heads
20+60=60 legs

6 0

3 years ago

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What is 100/200 + 300 - 700?

Karo-lina-s [1.5K]

Answer:

-399.5

Step-by-step explanation:

You divide, add, then subtract.

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3 years ago

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