Answer:
50
°
,
b
=
19
f
t
,
c
=
28f
t
Step-by-step explanation:
idk if im corecct or not (i think)
From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
The area under the speed curve tells you how much distance the vehicle covers.
The distance for first 30 s corresponds to the area of a rectangle with height <em>k</em> m/s and length 30 s, or
(<em>k</em> m/s) (30 s) = 30<em>k</em> m
The distance for the last 20 s corresponds to the area of triangle with height <em>k</em> m/s and length 20 s, or
1/2 (<em>k</em> m/s) (20 s) = 10<em>k</em> m
If the total distance traveled was 1.7 km = 1700 m, then
30<em>k</em> + 10<em>k</em> = 1700
40<em>k</em> = 1700
<em>k</em> = 42.5
Answer:
C) $25 + $1.25
Step-by-step explanation:
1. 51 x .5 = 25.5
2. 25.5 x .05 = 1.275
25 + 1.25 ≈ 25.5 + 1.28
Your answer will be D 0.60
A dollar is 1.00 so 0.60 will be 3/5
