All categories

2 years ago

How do you determine if an element is metal or non-metal?

Chemistry

2 answers:

snow_tiger [21]2 years ago

5 0

Answer: If the outermost shell has 1–4 electrons, it is a metal.

If the outermost shell has 5–7 electrons, it is a non-metal.

denpristay [2]2 years ago

3 0

Metal elements have 1,2,3 or 4 electrons in the outer most shell while non metals have 5,6 or 7 electrons.
Example - Carbon
atomic number - 6
electron configuration - 2,4
Meaning it has 4 electrons in its outer most shell which makes it a METAL.

You might be interested in

an element has 8 protons and 8 neutrons in its nucleus and 8 electrons revolving around the nucleus. What is the atomic number a

elena55 [62]

Atomic Number definition: The number of protons within the nucleus of x atom.

Atomic Mass definition: The number of protons and/+ neutrons within the nucleus of x atom.

The given information states that the element has 8 protons and 8 neutrons in its nuclei with 8 electrons revolving around it. If the atomic number is 'the number of protons' and we have 8 given protons, our answer would be 8. If the atomic mass is protons + neutrons and we have 8 protons and neutrons, our answer for atomic mass would inevitably be 16.

Therefore

Atomic number: 8

Atomic mass: 16

4 0

2 years ago

How do you determine the chemical reactivity for metals by using the periodic table?

vesna_86 [32]

Answer:

Chemical reactivity increases down a group and decreases from left to right of a period.

Explanation:

The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.

4 0

3 years ago

Help im stuck on this i dont understand

Hunter-Best [27]

A i think. not 100% sure

6 0

2 years ago

Read 2 more answers

Write the balanced reaction using the fewest whole number coefficients to describe the reaction between gaseous hydrogen and gas

Anastasy [175]

Answer: The percentage yield of water is 9.5 %

Explanation:

We are given:

Moles of hydrogen = 14 moles

Moles of oxygen = 10 moles

The chemical equation for the formation of water from hydrogen and oxygen follows:

$2H_2+O_2\rightarrow 2H_2O$

By Stoichiometry of the reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas

So, 14 moles of hydrogen gas will react with = $\frac{1}{2}\times 14=7mol$ of oxygen gas

As, given amount of oxygen gas is more than the required amount. So, it is considered as an excess reagent

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrogen gas produces 2 moles of water

So, 14 moles of hydrogen gas will produce = $\frac{1}{2}\times 14=7mol$ of water

To calculate the percentage yield of water, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of water = 1.33 moles

Theoretical yield of water = 14 moles

Putting values in above equation, we get:

$\%\text{ yield of water}=\frac{1.33mol}{14mol}\times 100\\\\\% \text{yield of water}=9.5\%$

Hence, the percent yield of the water is 9.5 %.

7 0

2 years ago

Which of the following compounds contains the Lead (II) ion? PbO PbCl4 Pb2O Pb2S

KATRIN_1 [288]

PbO Let's look at each of the 4 compounds and see what's needed. PbO. * Oxygen has a valance shell that's missing 2 electrons and wants to get those 2 elections. Lead donates them, so you have a Lead (II) ions. This is a correct choice. PbCl4 * Chlorine wants to grab 1 electron to fill it's valance shell and Lead donates that election. However, there's 4 chlorine atoms and every one of them wants and electron, and lead is donating all 4 of the desired electrons making the Lead (IV) ion. So this is a bad choice. Pb2O * Oxygen still wants 2 electrons and gets them from the lead. But there's 2 lead atoms and each of them donates 1 election making for 2 Lead(I) ions. So this too is a bad choice. Pb2S * Sulfur is in the same column of the periodic table as oxygen and if this compound were to exist would have similar properties as Pb2O and would have Lead(I) ions. So this is a bad choice.

6 0

3 years ago

Read 2 more answers