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SIZIF [17.4K]
3 years ago
15

A plane has a take off speed of 1 point

Physics
1 answer:
oksian1 [2.3K]3 years ago
4 0

Answer:

Acceleration = 1.85m/s²

Explanation:

Given the following data;

Final velocity = 300km/h to m/s = 300*1000/3600 = 83.33m/s

Time = 45 seconds

Since the plane started from rest, initial velocity is equal to 0m/s.

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Where,

a is acceleration measured in ms^{-2}

v and u is final and initial velocity respectively, measured in ms^{-1}

t is time measured in seconds.

Substituting into the equation, we have;

Acceleration = (83.33 - 0)/45

Acceleration = 83.33/45

Acceleration = 1.85m/s²

Therefore, the acceleration of the plane is 1.85m/s².

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A flat coil is in a uniform magnetic field. What angle between the magnetic field and the plane of the coil produces the maximum
Alecsey [184]

This question is incomplete, the complete question is;

A flat coil is in a uniform magnetic field. What angle between the magnetic field and the plane of the coil produces the maximum flux, and what angle produces 90% of the maximum flux

A) max: 0°

90% of max: 90°

B) max: 90°

90% of max: 45°

C) max: 90°

90% of max: 64°

D) max: 0°

90% of max: 26°

E) max: 90°

90% of max: 80°

Answer:

Option C) max: 90°

90% of max: 64°  is the correct Answer

Explanation:

from the Suppose Area is A.

then flux at angular position O is

Ф = BAsin∅

⇒ Ф = βmaxSin∅

flux will be max when sin∅ = 1

therefore sin∅ = 1

∅ = sin⁻¹ 1

∅ = 90°

Now at 90% of max flux

Ф ⇒ 0.9βmax = βmax sin∅

0.9 = sin∅

∅ = sin⁻¹ (0.9)

∅ = 64.15° ≈ 64°

Therefore Max ∅ = 90°

90% flux = 64°

Option C) max: 90°

90% of max: 64°  is the correct Answer

7 0
2 years ago
The motorcycle travels with a constant speed v0 along the path that, for a short distance, takes the form of a sine curve. Deter
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Let at any instant of time the speed is vo and the angle made by the bike with the horizontal is given

now we have

component of speed in x direction given as

v_x = v_0cos\theta

component of speed in y direction will be

v_y = v_0sin\theta

now from above two equations we can say that here

\theta = angle with the horizontal at any instant

and since here it is a sine curve so we know that

y = sin(x)

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6 0
3 years ago
A symbolic model for learning is a model that is observed in person.
kap26 [50]

Answer:

True

Explanation:

3 0
3 years ago
Read 2 more answers
How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?
DiKsa [7]
<span>Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
(1) => F = 68 * 1.2
F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)</span>
4 0
3 years ago
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An object with a mass m slides down a rough 370 inclined plane where the coefficient of kinetic friction is 0.20. If the plane i
Svetllana [295]

Answer:

v \approx 9.312\,\frac{m}{s}

Explanation:

The Free Body Diagram of the system is presented in the image attached below. The final speed is determined by means of the Principle of Energy Conservation and the Work-Energy Theorem:

K_{A} + U_{g,A} = K_{B} + U_{g,B} + W_{loss}

K_{B} = K_{A} + U_{g,A}-U_{g,B} - W_{loss}

\frac{1}{2}\cdot m \cdot v^{2} = m\cdot g \cdot s\cdot \sin \theta - \mu_{k}\cdot m \cdot g \cdot s \cos \theta

\frac{1}{2}\cdot v^{2} = g\cdot s \cdot (\sin \theta - \mu_{k}\cdot \cos \theta)

v = \sqrt{2\cdot g \cdot s \cdot (\sin \theta - \mu_{k}\cdot \cos \theta)}

v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (10\,m)\cdot (\sin 37^{\textdegree} - 0.2\cdot \cos 37^{\textdegree})}

v \approx 9.312\,\frac{m}{s}

3 0
3 years ago
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