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Papessa [141]
3 years ago
6

If u walk to school at a speed of 1.2 m/s and it takes you 18 min to reach the school, what is the distance from your home to th

e school?
Physics
2 answers:
Lapatulllka [165]3 years ago
7 0

Answer:

Explanation:

1 minute = 60 seconds

18 minutes = 18 * 60 sec = 1080 seconds

1 second allows 1.2 meters of a step

1080 second = x

1 / 1080 = 1.2 / x          Cross multiply

x = 1.2 * 1080

x = 1296 meters

I live 1296 meters from the school.

Reptile [31]3 years ago
3 0

Answer:

21.6m

Explanation:

Distance=speed×time

=1.2m/s×18min

=21.6m

Hope this helps u

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Answer:

\phi_B = 0.216 T m^2

Explanation:

As we know that the length of the conductor is given as

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now if it is converted into a square then we have

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now the are of the loop will be

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now the magnetic flux is defined as

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here we know

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\theta = 30.0^o

\phi_B = (1.0 T)(0.25 m^2)(cos30)

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3 years ago
A box rests on the (horizontal) back of a truck. The coefficient of static friction between the box and the surface on which it
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Answer:

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

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Using newton's second law

F = ma...(I)

Using formula of friction force

F= \mu m g....(II)

Put the value of F in the equation (II) from equation (I)

ma=\mu mg....(III)

a = \mu g

Put the value in the equation (III)

a=0.24\times9.8

a=2.352\ m/s^2

We need to calculate the distance,

Using equation of motion

s = ut+\dfrac{1}{2}at^2

s=0+\dfrac{1}{2}2.352\times(3.0)^2

s=10.584\ m\ approx\ 11\ m

Hence, The distance is 11 m.

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3 years ago
A boxed 12.0 kg computer monitor is dragged by friction 5.50 m up along the moving surface of a conveyor belt inclined at an ang
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How can astronomers infer approximately how long the universe has been expanding?
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a vehicle starts from rsst and after 10 seconds its velocity is 20m/s find the acceleration and the distance travelled.(step by
Naily [24]

Answer:

<u>Acceleration is 2 m/s² </u>

<u>Distance</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>0</u><u> </u><u>m</u>

Explanation:

From definition of acceleration, Acceleration is the rate of change in velocity.

• Simplifying the definition, or modifying it;

{ \boxed{ \rm{acceleration =  \frac{(final \: velocity - initial \: velocity)}{time} }}}

• Let's formulate symbols:

{ \boxed{ \rm{a =  \frac{v - u}{t} }}}

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  • u is initial velocity, u = 0 m/s [ at rest ]
  • t is time, t = 10 seconds

{ \rm{a =  \frac{20 - 0}{10}  =  \frac{20}{10} }} \\  \\{ \boxed{ \rm{ \: a = 2 \:  {ms}^{ - 2} }}}

Distance = ut + ½at²

Distance = (0 × 10) + (½ × 2 × 10²)

Distance = 0 + 10²

Distance = 100 meters

8 0
2 years ago
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