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kiruha [24]
3 years ago
7

If the earth were not tilted would there be seasons explain? Pls help

Biology
2 answers:
krek1111 [17]3 years ago
5 0

Answer:

No

Explanation:

If the earth was tilted, there would be small changes in temperature, but there will be no seasons. The Earth's axis is now inclined at around 24 degrees. This is the main reason for the changing of the seasons. The Northern Hemisphere is in the warm season when the Earth is slanted toward the sun, and the Northern Hemisphere is in the cold season when the Earth is slanted away from the sun. The cycle repeats itself every year because the Earth rotates around the sun at a known and generally constant rate. The sun is higher in the sky during the warm season, making it warmer, and lower in the sky during the cool season, making it colder.

Hope this helps :)

-jp524

Dmitry [639]3 years ago
4 0

Answer:

Um.................. What i think is No

Explanation:

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Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

<em><u>Genotype       Observed frequency</u></em>

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Use a 0.05 level of significance.

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Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.  

Explanation:

<u>Available data</u>:

  • Crossed genotypes: two
  • Genotypes among the offspring; Three → A, B, and C
  • Expected phenotypic ratio → 1:2:1
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  • B = 55 individuals
  • C = 27 individuals

So, let us first state the hypothesis:

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  • H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 ---------------  25% -------------X = 25 individuals A

2 --------------  50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

<u>                                                   A                             B                           C</u>

  • Observed                         18                            55                         27
  • Expected                         25                           50                         25
  • (Obs-Exp)²/Exp                1.96                        0.5                        0.16

<u>(Obs-Exp)²/Exp</u>

A)  (18 - 25)²/25 = 49/25 = 1.96

B)  (55 - 50)² / 50 = 25/50 = 0.5

C)  (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp  

  • ∑ is the sum of the terms
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X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05  

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99    

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Answer:

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Explanation:

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Different stages are involved in the allopatric speciation process:

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• Genetic divergence by natural selection and reproductive isolation,  impeding the two groups to mate even if the barrier disappears.  

• Prezigotic isolation mechanisms favored by selection a secondary contact between the new species occurs.

The Panama isthmus is an example of allopatric speciation caused by an extrinsic geological barrier that interrupted the genetic flow between species driving to genetic changes and reproductive isolation.  

Two different groups that evolved in allopatry might meet again in secondary contact if the barrier that separated them, disappears. In the Panama isthmus example, the groups that did mate, could not produce any fertile progeny because of postzygotic reproductive isolation. And the groups that did not mate, were not attracted to each other because of prezygotic reproductive isolation.  

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