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katrin [286]
3 years ago
5

What is the frictional force between a box and the floor it is being pulled across if, the kinetic coefficient of friction is 0.

27 and the box
weighs 38 N?
A 140.7 N
B 100.6 N
C. 37.7 N
D. 10.3 N
Physics
1 answer:
Artyom0805 [142]3 years ago
8 0

If the pulling is done parallel to the floor with constant velocity, then the box is in equilibrium. In particular, the weight and normal force cancel, so that

<em>n</em> = 38 N

The friction force is proportional to the normal force by a factor of 0.27, so that

<em>f</em> = 0.27 (38 N) ≈ 10.3 N

and so the answer is D.

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5 0
2 years ago
A heat engine has three quarters the thermal efficiency of a carnot engine operating between temperatures of 65°C and 435°C if
const2013 [10]

Answer:

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Explanation:

From the question we are told that

   The efficiency of the carnot engine is  \eta

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    The operating temperatures of the carnot engine is  T_1  =  65 ^oC =338 \ K  to  T_2 = 435  ^oC = 708 \  K

    The rate at which the heat engine absorbs energy is  P =  44.0 kW  = 44.0 *10^{3} \  W

Generally the efficiency of the carnot engine is mathematically represented as

          \eta =  [ 1 - \frac{T_1 }{T_2}  ]

=>       \eta =  [ \frac{T_2 - T_1}{T_2} ]

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Generally the efficiency of the heat engine is

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Here W is the work done which is mathematically represented as

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Here P_e  is the heat exhausted

So

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