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Sindrei [870]
3 years ago
7

PLEASE HELP ASAP Chet is creating a catapult that will allow him to propel a ball farther than he is capable of throwing it. As

he is creating the device, he finds that that catapult launches the ball straight up into the air. The catapult should propel the ball up and forward to create a trajectory.
Which of the following is the best solution to this problem?

A.
leave the design as is because the ball goes higher than he can throw it

B.
make changes to the design to allow it to launch the ball a farther distance

C.
discard the device and begin the engineering process again from the start

D.
leave the design as is but perform more tests to see if the problem improves
Chemistry
1 answer:
luda_lava [24]3 years ago
4 0

Answer:

IM NOT COMPLETELY SURE BUT ITS ETHER A OR B IM SORRY ;//

Explanation:

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Aleksandr [31]

Answer:    

Sb and Te

Explanation:

there are on the stair step

3 0
3 years ago
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The substance argon has the following properties: normal melting point: 83.9 K normal boiling point: 87.4 K triple point: 0.68 a
Vsevolod [243]

Answer:

The final state of the substance is a gas.

The sample is initially a liquid. One or more phase changes will occur.

Explanation:

Let's consider the phase diagram for Argon (not to scale).

<em>A sample of argon is initially at a pressure of 49.6 atm and a temperature of 101.4 K. The pressure on the sample is reduced to 0.680 atm at a constant temperature of 101.4 K. Which of the following are true? Choose all that apply </em>

<em>The final state of the substance is a gas.</em> TRUE. At 0.680 atm and 101.4 K, the substance is a gas.

<em>The gas initially present will solidify.</em> FALSE. Initially, Ar is present as a liquid.

<em>The final state of the substance is a solid.</em> FALSE.

<em>The sample is initially a liquid. One or more phase changes will occur.</em> TRUE. The sample is initially liquid and only one phase change will occur.

5 0
4 years ago
THIS IS A THREE PART QUESTION IF YOU CAN HELP IT WOULD BE REALLY APPRECIATED SO I DONT FAIL.
Nostrana [21]

Answer:

1. B = 1.13M

2. A. 8.46%

3. D = 0.0199

Explanation:

1. Molarity of a a solution = number of moles of solute/ volume of solution in L

Number of moles of solute = mass of solute/molar mass of solute

Molar mass of NaC₂H₃O₂ = 82 g/mol, mass of NaC₂H₃O₂ = 245 g

Number of moles of NaC₂H₃O₂ = 245 g / 82 g/mol = 2.988 moles

Molarity of solution = 2.988 mols/ 2.65 L = 1.13 M

2. Percentage by mass of a substance = mass of substance /mass of solution × 100%

Mass of 2.65 L of water = density × volume

Density of water = 1 Kg/L = 1000 g/L; volume of waterb= 2.65 L

Mass of water = 1000 g/L × 2.65 L = 2650 g

Mass of solution = mass of water + mass of solute = 245 + 2650 =2895 g

Percentage by mass of NaC₂H₃O₂ = 245/2895 × 100% = 8.46%

3. Mole fraction of NaC₂H₃O₂ = moles of NaC₂H₃O₂/moles of solution

Moles of water = mass /molar mass

Mass of water = 2650 g; molar mass of water = 18 g/mol

Moles of water = 2650 g / 18 g/mol = 147.222 moles

Moles of solution = moles of solute + moles of water = 147.222 + 2.988 = 150.21

Moles of NaC₂H₃O₂ =2.988 moles

Moles fraction of NaC₂H₃O₂ =2.988/150.21 = 0.0199

6 0
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the melting point of aluminum is 660 degrees Celsius.

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