Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol
<u>Answer:</u> The value of 
for the net reaction is 
<u>Explanation:</u>
The given chemical equations follows:
<u>Equation 1:</u> 
<u>Equation 2:</u> 
The net equation follows:
As, the net reaction is the result of the addition of first equation and the second equation. So, the equilibrium constant for the net reaction will be the multiplication of first equilibrium constant and the second equilibrium constant.
The value of equilibrium constant for net reaction is:
We are given:
Putting values in above equation, we get:
Hence, the value of for the net reaction is
Answer:
a) 0,014 min⁻¹
b) 1452 seconds.
c) 0,02156 M
d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction
Explanation:
a) For a first order reaction the half-life is:
<em>(1) </em>As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹
b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.
As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds
c) In the same way, 11072 years are 4 half-life for this reaction, thus:
0,345M/2⁴ = 0,02156 M
d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.
By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction
I hope it helps!
Answer:
For this assignment, I have picked three famous soccer players from around the world. I will go over their Birth, work ethic, and downfalls. I guess that most soccer players' downfalls are going to be their injuries.
The first soccer player I found was Ricardo Kakà. Ricardo Kakà was born to Simone dos Santos, his mother, and Bosco Izecson Pereira Leite, his father, on April 22, 1982. His work ethic mostly consists of "doing it". One of Ricardo Kakà's greatest downfalls is his injuries.
The second player I found was Cristiano Ronaldo. Cristiano Ronaldo was born to Maria Dolores dos Santos and José Dinis Aveiro. He was introduced to soccer by his dad because worked at a soccer field. Cristiano Ronaldo's work ethic consisted of something that Ricardo Kakà had as well. "Get it done". Cristiano Ronaldo's downfall was that his father drank too much.
I was not surprised to see that, but I thought it was going to be injuries as well.
The final player that I picked is Luis Suárez. Luis Suárez was born to Sandra Diaz and Rodolfo Suárez. He joined his local youth team that played soccer and he loved it. His work ethic is the same as the last soccer players. "Do it." His major downfall was that he was a bad-tempered teen and he got mad at stuff. That didn't help him when his parents divorced.
Overall all of the soccer players are different and very important. They have all gone through different situations and have gotten through them through soccer.
Explanation:
This is not 300 words, it is 244. You can it. Make sure to change it so it sounds like you wrote it.
