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3 years ago

Al-Qaeda is the name of the group that fought against the Soviet-supported government in Afghanistan.

Chemistry

1 answer:

topjm [15]3 years ago

4 0

False it is a terrorist group in Afghanistan and put 911 in ny

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A gallon of paint covers 350 square feet.

trapecia [35]

Answer:

2,137... gallons

Explanation:

(160+140+14x16x2)/350=2,137...

4 0

2 years ago

How many mono-; di- ; and trichloro derivatives are possible for cyclopentane?

Studentka2010 [4]

Mono - 1 Di- 2 Tri - 4

8 0

3 years ago

Which of these is not a biomass source?

liberstina [14]

A biomass source is an natural material.

The sun is natural.

Manure is natural.

Wood Chips are natural.

Paper is natural and treated with unnatural substances.

7 0

3 years ago

Read 2 more answers

Plz someone help, really struggling

frez [133]

Answer:

22.9 Liters CO(g) needed

Explanation:

2CO(g) + O₂(g) => 2CO₂(g)

? Liters 32.65g

= 32.65g/32g/mol

= 1.02 moles O₂

Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)

∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)

Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.

∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed

___________________

*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).

6 0

2 years ago

Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th

WINSTONCH [101]

Answer: The standard enthalpy change of the reaction is coming out to be -16.3 kJ

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]$

We are given:

$\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ$

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0

3 years ago