Answer:
Explanation:
An electron accelerates through a 12.5 V potential difference, starting from rest, so it will acquire kinetic energy of 12.5 eV .
In hydrogen atom energy of n th orbit in terms of eV is given as follows
En = -13.6 / n² eV
Total energy of 1 st orbit E₁ = - 13.6 eV
Total energy of 2 st orbit E₂ = - 13.6 eV / 2² = - 3.4 eV
Total energy of 3 st orbit E₃ = - 13.6 eV / 3² = - 1.5 eV
Total energy of 4 st orbit E₄ = - 13.6 eV / 4² = - 0.85 eV
E₄ - E₁ = 13.6 - 0.85 = 12.75 eV
E₃ - E₁ = 13.6 - 1.5 = 12.10 eV
E₂ - E₁ = 13.6 - 3.4 = 10.2 eV .
The electron has energy of 12,5 eV so it can excite electron from E₁ to E₃ . .
Jump possible = E₃ to E₂ , E₂ to E₁ and E₃ to E₁
Energy of E₃ to E₂ = 3.4 - 1.5 eV = 1.9 eV
wavelength = 1237 / 1.9 nm = 651 nm
E₃ - E₁ = 13.6 - 1.5 = 12.10 eV
wavelength = 1237 / 12.10 nm = 102.23 nm
E₂ - E₁ = 13.6 - 3.4 = 10.2 eV
wavelength = 1237 / 10.2 nm = 121.27 nm
wavelength of photon possible are 651 nm , 121.27 nm , 102.23 nm .
