Answer:
A) E = 3.70*10^{4} N/C
B) E = 2.281*10^3 N/C
Explanation:
given data:
charge density 
length of wire = 9.50 cm
a) at x = 4.5 m above midpoint, electric field is calculated as

x = 4.5 cm
midpoint a = 4.5 cm = 0.0475 m

E = 3.70*10^{4} N/C
B) when wire is in circle form


= 1.235*10^{-8} C
Radius of circle


r = 1.511*10^{-2} m


E = 2.281*10^3 N/C
Answer:Divergent boundaries are areas where plates move away from each other, forming either mid-oceanic ridges or rift valleys. Tectonic plates can interact in one of three ways. They can move toward one another, or converge; move away from one another, or diverge; or slide past one another, a movement known as transform motion. All plate margins along which plate movement is occurring have one thing in common—earthquakes.
Answer:
orbitals
Explanation:
The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.
Given info
d = 0.000250 meters = distance between slits
L = 302 cm = 0.302 meters = distance from slits to screen
= angle to 8th max (note how m = 8 since we're comparing this to the form
)
(n = 5 as we're dealing with the 5th minimum )
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Method 1

Make sure your calculator is in degree mode.
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Method 2

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Method 3

There is a slight discrepancy (the first two results were 611 nm while this is roughly 613 nm) which could be a result of rounding error, but I'm not entirely sure.
The answer is D. If you aren't consistent with your drop positions, then your data may be invalid. To be frank: it basically screws over the experiment.