Answer:
1. 0.178 moles ; 2. 8x10²³ atoms ; 3. 7.22x10²³ molecules ; 4. 89.6 g ; 5. 1.34x10²² atoms ; 6. 1.67x10²⁵ molecules
Explanation:
1. Mass / Molar mass = Mol
5g / 28 g/m = 0.178 moles
2. 1 molecule of N₂ has 2 atoms, it is a dyatomic molecule.
4x10²³ x2 = 8x10²³ atoms
3. 1 mol of anything, has 6.02x10²³ particles
6.02x10²³ molecules . 1.2 mol = 7.22x10²³
4. 1 atom of C weighs 12 amu.
4.5x10²⁴ weigh ( 4.5x10²⁴ . 12) = 5.24x10²⁵ amu
1 amu = 1.66054x10⁻²⁴g
5.24x10²⁵ amu = (5.24x10²⁵ . 1.66054x10⁻²⁴) = 89.6 g
5. Molar mass NaCl = 58.45 g/m
1.3 g / 58.45 g/m = 0.0222 moles
1 mol has 6.02x10²³ atoms
0.0222 moles → ( 0.0222 . 6.02x10²³) = 1.34x10²²
6. Density of water is 1 g/mL, so 500 mL are contained in 500 g of water
Molar mass H₂O = 18 g/m
500 g / 18 g/m = 27.8 moles
6.02x10²³ molecules . 27.8 moles = 1.67x10²⁵
Oxygen 47 Hydrogen 63
Silicon 28 Oxygen 25.5
Aluminum 7.9 Carbon 9.5
Iron 4.5 Nitrogen 1.4
Calcium 3.5 Calcium 0.31
Sodium 2.5 Phosphorus 0.22
Potassium 2.5 Chlorine 0.03
Magnesium 2.2 Potassium 0.06
Titanium 0.46 Sulfur 0.05
Hydrogen 0.22 Sodium 0.03
Carbon 0.19 Magnesium 0.01
All others <0.1 All others <0.01 Living matter
Answer:
d.- The model does not provide information about the type of rock in which fossils form.
Explanation:
The fossils can be located in different parts like on land, shore and water. But, they were formed at different time, that means, they live in different ages, that is the reason why the model need to include the type of rock. Remember fossil form at different ages and with the pass of time different layers of rock formed.
Hope this info is useful.
I don’t get it what do u need exactly?
Answer:
4000mL
Explanation:
Using the combined gas law equation as follows:
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (mL)
V2 = final volume (mL)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information given in this question:
V1 = 1000mL
T1 = 20K
P1 = 1.0atm
V2 = ?
P2 = 0.5atm
T2 = 40K
Using P1V1/T1 = P2V2/T2
1 × 1000/20 = 0.5 × V2/40
1000/20 = 0.5V2/40
50 = 0.5V2/40
50 × 40 = 0.5V2
2000 = 0.5V2
V2 = 2000/0.5
V2 = 4000mL
