Answer: The density of Uranium Hexafluoride at 60 °C and 745 torr is 0.0127 g/ml
Explanation:
Uranium Hexafluoride is only present as gas at 60 °C and 745 torr.
So, we know PV = nRT, from that
n/V = P/ RT = (745 torr)/(62.36 L-torr/mol*K)(337 K) = 0.0354 mol/L.
Density = (352.02 g/mol)(0.0354 mol/L)/(1000 cm³/L) = 0.0127 g/cm³
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The correct answer is A. A test tube of zinc oxide. Zinc oxide is a compound which is a pure substance composed of two or more elements. They can only be separated or broken down into its individual elements or smaller compounds by chemical means. Therefore, the answer is a test tube of zinc oxide.
Answer:
94.44
Explanation:
Volume is equal to Mass/Density so therefore, you do the mass which is 68.0 g/0.72 g/mL which is the density and get 94.44 mL because the g cancel each other out when it comes to the label!
In the reactants Sb has oxidatin number 0 (because it is in its elemental form)
In the products Sb has oxidaton number +3.
Then Sb lost electrons which means it oxidized.
According to the plum pudding model of the atom proposed by J.J. Thomson, the atom was considered to be a positive charge sphere in which electrons (negatively charged) are embedded in order to balance the positive charge.
According to Rutherford’s gold foil experiment, when he bombarded particles to the gold foil he observed that most of the particles went through, some of them got scattered in various directions, and few are deflected back to the source. Hence, this experiment shows that the plum pudding model was incorrect as; if there was the symmetrical distribution of the charges then all the particles will pass through without any deflection.