PH = -log([H+])
[H+] = 10^(-pH)
[H+] = 10^(-8.78) = 1.65*10^-9
[H+][OH-] = Kw
Kw = 1.0*10^-14 at 25 degrees celsius.
[OH-] = Kw/[H+] = (1.0*10^-14)/(1.65*10^-9) = 6.06*10^-6
The concentration of OH- ions is 6.1*10^-6 M.
When a volume of 60.0 mL of 0.200 M HBr is mixed with a volume of 30.0 mL of 0.400 M CH3NH2, The pH value is mathematically given as
pH=10.64
<h3>What is
the pH value when 60.0 mL of 0.200 M HBr is mixed with 30.0 mL of 0.400 M CH₃NH₂?</h3>
Question Parameters:
The pH when 60.0 mL of 0.200 M HBr
30.0 mL of 0.400 M CH₃NH₂ (Kb = 4.4 × 10^{-4}).
Generally, the equation for the Chemical Reaction is mathematically given as
H Br + H_3C NH_2----- > CH_3 NH_3 Br
Therefore
oH=p^{kb}+-log
OH=-log(4.4*10^{-4})+
OH=3.36
In conclusion, The equation pH value
pH+OH=14
Therefore
pH+=14-3.36
pH=10.64
Read more about Chemical Reaction
brainly.com/question/11231920
Answer:
False
Explanation:
Changing the coefficients is one of the steps of balancing a chemical equation. Changing the subscript changes the compounds being used, while changing the coefficient changes the amount of each compound being used.
The mixture will be 'homogeneous mixture' if you dissolve a spoonful of salt into a bucket of water and mix it well to from a solution.
Hope this helps!