Answer:
A is denser than B as it's volume for the same mass is smaller.
Explanation:
Hello.
In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:
Next, we compute the densities as shown below:
In such a way, A is denser is B as it's volume for the same mass is smaller.
Best regards.
The acids found in alcohol that make it evaporate are called organic acids.
An organic acid is an organic compound that has acidic properties. There are two types: one has a carboxyl (COOH) group, and the other type has a phenol group.
The most common organic acids are those with a carboxyl group and include acetic acid, formic acid, lactic acid and all fatty acids. Perfumes include organic acid in their composition to make them volatile. Volatile substances evaporate easily, and this is important for perfumes. They need to dissipate easily into the surrounding environment and spread their good smell.
Answer:
6.02*10^23
Explanation:
This is the number for one mole. Just like one dozen = 12, one mole = 6.02*10^23.
Fun fact, if you had a mole of pennies you could spend 1 million dollars every second of your life and not have even spent 1% of it by the time you die at 100 years old.
Answer:
c. precipitation
Explanation:
Let's consider the following balanced net ionic equation.
Cl⁻(aq) + AgNO₃(ag) ⇒ AgCl(s) + NO₃⁻ (ag)
What kind of reaction is this?
a. acid-base. No, because the reactants are not acids and bases.
b. redox. No, because all the species have the same oxidation numbers in the reactants and the products
c. precipitation. Yes, because an insoluble compound (AgCl) is produced, which then precipitates.
Answer:
1.) 13 g C₄H₁₀
2.) 41 g CO₂
Explanation:
To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O
48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 13 g C₄H₁₀
48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 41 g CO₂
