Heat required = 173 kJ
<h3>Further explanation</h3>
Given
56.0 g of ice
Temperatur at 263 K(-10 C) to 400 K(127 C)
Required
Heat needed
Solution
1. raise the temperature(-10 C to 0 C)⇒c ice=2.09 J/g C
2. phase change (ice to water)⇒Heat of fusion water=334 J/g
3. raise the temperature(0 C to 100 C)⇒c water= 4.18 J/g C
4. phase change(water to vapor)⇒heat of vaporization water=2260 J/g
5. raise the temperature(100 C to 127 C)⇒c vapor=2.09 J/g C
Total heat :
1170.4+18704+23408+126560+3160.08=173,002.48 J=173 kJ
The last option, 1 meter/ 10 millimeters is not a valid conversion factor.
It should be 1000m Instead of 1 meter/ 10 millimeter since 1m=1000mm
2Ca3(PO4)2 + 6SiO2 + 10C ---> P4 + 6CaSiO3 + 10CO
1 mole of Ca3(PO4)2 = 310g
1 mole of P4 = 124g
according to the reaction:
2*310g Ca3(PO4)2----------------124g P4
x g Ca3(PO4)2 ------------------------ 30g P4
x = 150g Ca3(PO4)2
so, your answer is good
Answer:
Mechanism for top reaction is combustion while the side product at bottom path oximes
Explanation:
Hydroxiamine is a reducing agent that requires high temperature to combust in it'd ageous state to produced oxime while water is eliminated. The reverse is the case because the production of water during combustion I does not yield the fight result as it can e very irritating.
Increased temperature stimulates the protons to become free to combust and react with 2 butene and other aldehyde during chemical reaction.
Answer:
If there was only 10 hours in a day, including the night time it would be complexly new environment. Say you are up for 7 hours and sleep 3, in those 7 hours you would go to work for probably 4 hours, come home and do stuff for 3 then go to bed and do it all over again.
