<u>Answer:</u> The amount of heat required to warm given amount of water is 470.9 kJ
<u>Explanation:</u>
To calculate the mass of water, we use the equation:

Density of water = 1 g/mL
Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:

To calculate the heat absorbed by the water, we use the equation:

where,
q = heat absorbed
m = mass of water = 1500 g
c = heat capacity of water = 4.186 J/g°C
= change in temperature = 
Putting values in above equation, we get:

Hence, the amount of heat required to warm given amount of water is 470.9 kJ
Answer:
Sodium is a silvery-white metal that reacts with chlorine gas, which is a yellow-greenish gas that is toxic. The reaction gives off a lot of heat. After the reaction, which statement is true about the chemical properties of the product, sodium chloride?
Pure sodium reacts violently and sometimes explosively with water producing sodium hydroxide, hydrogen gas and heat
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
Chlorine is a very poisonous yellow green gas with a sharp odour that was used in gas warfare during WW1
Sodium and chlorine reacts with each other, however, to produce one of the most familiar substance used in cooking and preservation industry today Sodium Chloride or Common salt or table salt in the irreversible equation;
2Na(s) + Cl2(g) → 2NaCl(s)
Explanation:
It is easy to see why this reaction takes place so readily sodium has one electron in its outermost valence shell while chlorine has seven electrons in its valence shell. when sodium atom transfers one electron to chlorine atom forming a sodium cation (Na+) and a chloride anion (Cl-) both ions have complete valence shells and are energetically more stable. the reaction is extremely exothermic, producing a bright yellow light and a great deal of heat and fumes of sodium chloride.
In a reaction observation of the reaction process you will see sodium flares up almost immediately upon reaction with water.
In a neutral ionic compound, you can determine its sub-scripts by simply flipping the ionic charges and dropping the signs: so AlS would be Al2S3
Answer:
0.39 moles
Explanation:
To find how many moles are in 50.0 g of CaC₂O₄ you divide the grams of the sample by the molar mass of the compound;
=0.39 mol
The grams cancel out and you are left with moles!
I hope this help ^-^