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lakkis [162]
3 years ago
14

How many significant figures should the following answer have? (23.34 cm)(90076 cm)(2.1223 cm) = cm

Chemistry
2 answers:
bezimeni [28]3 years ago
8 0

Answer : The number of significant figures are, four (4).

Explanation :

The rule apply for the multiplication and division is :

The least number of significant figures in any number of the problem determines the number of significant figures in the answer.

As we are given :

(23.34cm)\times (90076cm)\times (2.1223cm)

\Rightarrow 4462000cm^3

In this problem, the least number of significant figures is 4.

So, the correct answer is, 4.462\times 10^{6}cm^3

Hence, the number of significant figures are, four (4).

Yuri [45]3 years ago
4 0
4 - due to being a multiplication problem the answer goes to the least amount of Sig Figs given in a previous number.
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Answer:- 1467 K

Solution:- It asks to calculate the kelvin temperature of the light bulb. Looking at the given info, it is based on ideal gas law equation, PV=nRT.

Given: n=7.16*10^-^4moles

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We know that, 101.325 kPa = 1 atm

So, 116.8kPa(\frac{1aym}{101.325kPa})

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R is universal gas constant and it's value is 0.0821\frac{atm.L}{mol.K} .

T = ?

Let's plug in the values in the equation and solve it for T.

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The answer is 24 solutions are needed
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What is the main point of mutation ? <br> quick please !!
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g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o
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Answer:

<u><em></em></u>

  • <u><em>pOH = 0.36</em></u>

Explanation:

Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.

<u>1. Potassium hydroxide solution, KOH</u>

  • Volume, V = 304 mL = 0.304 liter
  • Molarity, M = 0.36 M
  • number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol
  • 1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

<u>2. LIthium hydroxide, LiOH</u>

  • Volume, V = 341 mL = 0.341 liter
  • Molarity, M = 0.51 M
  • number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol
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<u />

<u>3. Resulting solution</u>

  • Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

  • Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

  • Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

<u />

<u>4. </u><em><u>pOH</u></em>

      pOH=-\log [OH^-]=-\log (0.439)=0.36   ← answer

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Explanation:

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