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2 years ago

Which is the molar mass of NH₄MnO₄?

Chemistry

1 answer:

WINSTONCH [101]2 years ago

3 0

Answer:

Molar Mass, Molecular Weight and Elemental Composition Calculator Enter a chemical formula to calculate its molar mass and elemental composition: Molar mass of NH4MnO4 is 136.9741 g/mol

Explanation:

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Match the following reactions with the reaction type. You may use each type more than once.

vaieri [72.5K]

Answer:

1) Decomposition

2)Double-replacement reaction

3)synthesis

4)Double-replacement reaction

5)single-replacement reaction

6)Double-replacement reaction

Explanation:

Step 1: Data given

Synthesis: This is a reaction where two or more reactants will combine to form a new, single product. This is occurs when two or more reactants combine to form a single product. This can be shown with the following equation.

A + B → C

A and B are the reactants to form a new product C

Decomposition: This is a reaction where 1 (more complex) compound will be broken down into 2 or more (more simple) products.

This can be shown by the following equation:

AB → A + B

A single replacement: This is a reaction where one element wil be replaced by another element in the same compound. This can be shown by the following equation:

A + BC → B + AC

Here is the elemnt B in the compound BC, replaced by the element A, to form a new compound AC

A double-replacement: This is a reaction where the positive and negative ions of two ionic compounds will be exchanged and 2 new compounds willbe formed. This can be shown by the following equation:

AB+CD→AD+BC

A combustion reaction requires oxygen gas (O2) to produce the products CO2 and H2O

Step 2:

1) 2HgO(s) → 2Hg(l) + O2(g)

⇒ Decomposition

2) KCl(aq) + AgNO3(aq) → AgCl(s) + KNO3(aq)

⇒ Double-replacement reaction

3) 2Na(s) + H2(g) → 2NaH(s)

⇒ synthesis

4) Mg(OH)2(aq) + 2HNO2(aq) → Mg(NO2)2(aq) + 2 H2O(l)

⇒ Double-replacement reaction

5) Ca(s) + 2AgNO3(aq) → Ca(NO3)2(aq) + Ag(s)

⇒ Single-replacement reaction

6) Al2O3(s) + H2SO4(aq) → Al2(SO4)3(aq) + H2O(l)

⇒ Double-replacement reaction

8 0

3 years ago

What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?

Mama L [17]

Answer:

C: $\frac{6 mol}{2 L}$

Explanation:

we can use the molarity equation

$M = \frac{mol}{L}$

so to find M we plug in what we know, which is 6 moles of NaCl and 2 L of water, which gives us:

$\frac{6 mol}{2 L}$

8 0

2 years ago

How are bones important to the lymphatic system?

Marianna [84]

Our bone marrow continuously makes new red and white blood cells. The lymphatic system consists of the bone marrow, the spleen, the thymus (in young people), and lymph nodes.

7 0

3 years ago

How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?

Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

$pH= -log[H]\\pH= -log (\frac{kw}{[OH]})$

$8.23 = - log(\frac{Kw}{[OH]} \\10^{-8.23} = Kw/[OH]\\ [OH] = Kw/10^{-8.23}$

$[OH]=1.69E-6$

This concentration of OH affects the disociation of Cu(OH)2. Let us see the dissociation reaction:

$Cu(OH)_2 -> Cu^{2+} + 2OH^-$

In the equilibrum, exist a concentration of OH already, that we knew, and it will be added that from dissociation, called "s":

The expression for Kps is:

$Kps= [Cu^{2+}] [OH]^2$

The moles of (CuOH)2 soluble are limitated for the concentration of OH present, according to the next equation.

$Kps= s*(2s+1.69E-6)^2$

"s" is the soluble quantity of Cu(OH)2.

The solution for this third grade equation is $s=4.96E-8 mol/L$

Now, let us calculate the moles in 1 L:

$moles Cu(OH)_2 = 4.96E-8 mol/L * 1 L = 4.96E-8 moles$

7 0

3 years ago

You witnessed a slide breaking while someone is using a microscope.The silde was not dropped.You are tasked with finding out why

Evgesh-ka [11]

Answer:

See the answer below

Explanation:

The slide could have broken due to the ramming of the objective (especially the high power objectives) into the slide on the stage of the microscope while trying to bring the object on the slide into focus.

It is recommended to start with the lowest objective while trying to focus a slide. Thereafter, the next higher objective can be switched to and the image brought into focus once again. This can be repeated until the desired magnification of the image is reached.

However, at higher objective powers, the coarse adjustment knob should be avoided to avoid the objectives touching/breaking the slide. Instead, the fine adjustment knob should be used.

Hence, the breaking of the slide in the illustration could have been due to the use of the coarse adjustment knob at higher objective powers and the ramming of the objective into the slide.

3 0

3 years ago