Actual yield of Fe2(So4)3 = 18.5g
2FePo4 + 3Na2SO4 -> Fe2(SO4)3 + 2Na3PO4
Mole of FePO4 = mass of it / its molar mass =
25 g / (55.8 + 31 + 16*4) = 0.166 mol
every 2 mole of FePO4 will form 1 mole of Fe2(SO4)3
Mole of Fe2(SO4)3 produced = 0.166 / 2 = 0.0829 mol
0.0829 * (55.8*2 + 3*(32.1+ 16*4)) = 33.148 g of Fe2(SO4)3
18.5 / 33.148 * 100 = 55.8%
Answer: - 0.75
Explanation:
For this question, you must remember that a fraction can be written of division.
So, -3/4 = -0.75, between -0.7 and -0.8 on the number line.
Igneous <span>rock ! Of course oh how i miss middle school.........</span>
Answer:
<h2>
<u>natural</u></h2>
Explanation:
hope this helps you!!
mark as brainliest please
I think its density is 850kg/m^3
