Answer:
- <u><em>294.307 g/mol</em></u>
Explanation:
The first question for this statment is:
- <em>Calculate the gram-formula-mass of aspartame. </em>
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<h2>Solution</h2>
The chemical formula is:
The <em>gram-formula-mass </em>is calculated adding the masses for all the atoms in the molecular formula:
Atom Number of atoms Atomic mass Total mass
g/mol g/mol
C 14 12.011 14 × 12.011 = 164.154
H 18 1.008 18 × 1.008 = 18.144
N 2 14.007 2 × 14.007 = 28.014
O 5 15.999 5 × 15.999 = 79.995
===================
Total 294.307 g/mol
Answer: 294.307 g/mol
Answer:
1 mole of gas = 22.4L
2.5 moles of gas takes up = ( 22.4 L/ 1 mole ) x 2.5 mole
= 56 L
Explanation:
Please mark brainliest and have a great day!
The answer from this questions is the letter
B. He should not use his opinions as evidence.
Answer:
36.92 mg of oxygen required for bio-degradation.
Explanation:
Mass of benzene = 30 mg = 0.03 g (1000 mg = 1 g )
Moles benzene =
According to reaction 5 moles of benzene reacts with 15 moles of oxygen gas.
Then 0.0003846 mol of benzene will react with:
of oxygen gas
Mass of 0.0011538 moles of oxygen gas:
0.0011538 mol × 32 g/mol = 0.03692 g = 36.92 mg
36.92 mg of oxygen required for bio-degradation.
Answer:
Hey hi
Explanation:
Can you pls tell me which language is this pls I really want to help you... Sorry
