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tresset_1 [31]
3 years ago
14

What is the part of the earth that includes the solid crust and the rigid uppermost part of the martle

Chemistry
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

I can't understand

Explanation:

sorry this

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A technician measures the weight of a reagent . The weight is 3269 g. What is the weight in kilograms ? Write your answer as a d
Georgia [21]

Answer:

3.269 kg

Explanation:

1000g = 1 kg. Since kg is the larger unit, you need to divide by 1000 to get kilograms. You can do the problem as a unit conversion:

3269 g × <u>1 kg</u>  =  3.269 kg

                1000g

Hope this is helpful!

5 0
3 years ago
If the pKa value for a given acid is low, what does that say about the acid (is it weak or strong)?
Dmitry [639]

Answer:

If the pKa of the acid is low (negative), then the acid is strong.

Explanation:

Ka, <em>the acid ionization constant,  </em>measures the strength of an acid in a solution. Stronger acids have higher Ka values.

We defined: pKa = -log[Ka]

This function is a decreasing function, meaning that pKa will be getting smaller and smaller,  while increasing Ka (high values of Ka will have negative pKa values). Therefore, stronger acids (high values of Ka), will have low (negative) pKa values.

3 0
3 years ago
The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins
saul85 [17]
The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. (1/2)^{n} = x,
where:
<span>n - a number of half-lives
</span>x - a remained fraction of a sample

2. t_{1/2} = \frac{t}{n}
where:
<span>t_{1/2} - half-life
</span>t - <span>total time elapsed
</span><span>n - a number of half-lives
</span>
So, we know:
t = 10 min
<span>t_{1/2} = 2.5 min

We need:
n = ?
x = ?
</span>
We could first use the second equation to calculate n:
<span>If:
t_{1/2} = \frac{t}{n},
</span>Then: 
n = \frac{t}{ t_{1/2} }
⇒ n = \frac{10 min}{2.5 min}
⇒ n=4<span>
</span>
Now we can use the first equation to calculate the remained fraction of the sample.
<span>(1/2)^{n} = x
</span>⇒ x=(1/2)^4
<span>⇒x= \frac{1}{16}</span>
3 0
3 years ago
Some forms of vitamin D, C₂₈H₄₄O, can be found in red meat. How many total atoms are in 5 molecules of C₂₈H₄₄O
MaRussiya [10]

Answer:

3.01 × 10^24 atoms of vitamin D

Explanation:

The number of atoms, molecules or ions present in a substance is given by the Avogadro's number which is 6.02 × 10^23.

Hence;

1 molecule of vitamin D contains 6.02 ×10^23 atoms

5 molecules of vitamin D contains 5 × 6.02 ×10^23/1

= 3.01 × 10^24 atoms of vitamin D

7 0
3 years ago
Use the Debye-Huckel Equation to calculate the activity coefficient of Ce4+ at μ = 0.070 M.
Dmitriy789 [7]

english please so i can help

8 0
3 years ago
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