In order to compare you must multiply the the bottom two by each other and then multiply the top one by the same number you multiplied the bottom one by. The answer is not equal because the first fraction is 6/15 and the second is 5/12.
Answer: Area of Δ DUO = 12.0 square units.
Step-by-step explanation:
From the diagram, Δ DPA is a right angled triangle and right angled at P.
Therefore ∠D will be
Tan ∅° = PA/DP ie, opposite side all over the adjacent.
= 4.5/3.75
Tan∅° = 1.2
to calculate ∅°, we know find the inverse of Tan 1.2
∅ = Tan^-1 1 .2 from your log tables or calculator
∅° = 50.20°.
= 50°
Since line DR is ⊥ to line OP
∠ADR = 90° - 50°
= 40°.
From the diagram,
∠ADR = ∠UDR = 40°
Therefore,
∠ODU = 180 - ( 40 + 40 + 90 ) { Angle on a straight line }
= 180 - 170
= 10°
From Δ UDM , line MU is he height of the required Δ DUO whose area is to be determined.
Now find the height MU
Tan10.0° = MU/10, where MU is the opposite side and 10.0 is the adjacent from the diagram given.
MU = Tan10.0 x 10.0
= 0.1763 x 10.0
= 1.763
Therefore to calculate the area of Δ DUO
= 1/2 x base x height
= 1/2 x line OD x line MU
= 1/2 x 14.0 x 1.763
= 7 x 1.763
= 12.341
= 12.0 square units.
=
Answer:
0.05
Step-by-step explanation:
We know that the number of marbles is represented by n. We also know that as the number of marbles increases, the volume of water W(n) decreases, since 0.05n is subtracted.
Since 0.05n is subtracted from 32, then 32 must be the original amount of water used if there are no marbles.
Since the amount of water decreases by 0.05 times the number of marbles, the volume of each marble must be 0.05.
M=21 that should equal -15