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goblinko [34]
3 years ago
7

This one is a bit long but I am desperate!

Chemistry
1 answer:
Ivanshal [37]3 years ago
7 0
<span>a) Oxidation state of Ba in reactant: 0
In product: +2.
</span><span>Oxidation state of Zn in reactant: +2.
In product: 0.
</span><span>Oxidation state of S in reactant: +6
In product: +6.
</span><span>Oxidation state of O in reactant: -2.
In product: -2.
This is redox reaction because elements change their oxidation states (barium and zinc).
</span>b) Oxidation reaction: Ba⁰ → Ba²⁺ + 2e⁻.
Reduction reaction: Zn²⁺ + 2e⁻ → Zn⁰.
c) Barium is oxidized (increase of oxidation number) and zinc is reduced (decrease of oxidation number).
d) <span> The oxidizing agent is zinc (gain electrons) and the reducing agent is barium (lose electrons).</span>
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