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Anastasy [175]
3 years ago
9

Explain how you can use physical properties to compare substance

Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0
You can use physical properties to compare substance by the texture depending on how rough, hard, soft etc
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A gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from blank
lidiya [134]

Answer: -

1.34 L

Explanation: -

Initial Pressure P 1 = 39.1 bar

Initial Temperature T 1 = 643 K

Let the initial volume be V 1.

Final pressure P 2 = 87.0 bar

Final temperature T 2 = 525 K.

Final volume V 2 = 0.492 L

Using the equation

\frac{P1 V 1}{T1} = \frac{P 2 V 2}{T2}

V 1 = \frac{P2 V2 T1}{P 1 T2}

Plugging in the values

We have

V 1 = 87 bar x 0.492 L x 643 K / (39.1 bar x 525 K)

= 1.34 L

Thus, a gas is contained in a thick-walled balloon. When the pressure changes from 39.1 bar to 87.0 bar the volume changes from 1.34 L to 0.492L and the temperature changes from 643K to 525K

4 0
4 years ago
Read 2 more answers
What volume of 15.9 M Nitric acid would be required to make 7.2 L of 6.00 M nitric acid? (hint: dilution problem) will mark brai
irakobra [83]

Answer:

d

Explanation:

8 0
3 years ago
Draw a Lewis dot structure of the bonds between atoms in a molecule of this product. Use a - (dash) to represent a bonding pair.
Alina [70]
Ensure O has stable octet configuration

3 0
3 years ago
What is the pH of a solution of 0.900 M KH2PO4, potassium dihydrogen phosphate? Express your answer numerically to the hundredth
stepan [7]
4.67 is the right answer

+ − − log(7,5 ∗ 10−3) − log(6.2 ∗ 10−8) ,34 ,24
= 2 = 2 =4.67
3 0
3 years ago
For the reaction of 2Na2O, if you have 18.0 g of Na, how many grams of O2 are needed for reaction?
geniusboy [140]

Answer: -

6.26 grams

Explanation: -

Atomic Mass of sodium Na = 23 gram

Mass of Na = 18 g

Atomic mass of oxygen O = 16 gram

Molar mass of O2 = 16 x 2 = 32 gram

The balanced chemical equation for the reaction is

4 Na + O2 -- > 2 Na 2 O

From the balanced chemical equation, we see

4 Na requires 1 O2

4 x 23 gram of Na requires 32 gram of O2

18 g of Na gives \frac{32 g O 2 x 18 g Na}{4 x 23 gram Na}

= 6.26 grams of O2

For the reaction of formation of Na2O, for 18.0 g of Na, 6.26 grams of O2 are needed for reaction.

8 0
3 years ago
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