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dybincka [34]
2 years ago
11

What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and

second carbons. nonene nonane 1-octyne 1-octene
Chemistry
1 answer:
yKpoI14uk [10]2 years ago
8 0

The name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.

<h3>Nomenclature of Organic compounds</h3>

From the question, we are to determine the name of the given molecule.

To name the compound, we will follow the IUPAC rules.

Some of IUPAC rules are

  • Find the longest continuous carbon chain. Determine the root name for this parent chain.
  • For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.

The given compound has 8 carbons and a double bond. The root name of the compound is octane.

By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.

Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.

Hence, the name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.

Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333

The diagram for the compound is attached below.

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3 years ago
Suppose 0.708g of copper(II) acetate is dissolved in 50.mL of a 46.0mM aqueous solution of sodium chromate.
lisabon 2012 [21]

Answer:

The final molarity of acetate anion in the solution is 0.0046 moles

Explanation:

The balanced equation is

Cu(C₂H₃O₂)₂ + Na₂CrO₄ = CuCrO₄ + 2Na(C₂H₃O₂)

Therefore one mole of Cu(C₂H₃O₂)₂ react with one mole of Na₂CrO₄ to form one mole of CuCrO₄ and two moles of Na(C₂H₃O₂)

Mass of copper (II) acetate present = 0.708 g

Volume of aqueous sodium present = 50 mL

Molarity of sodium chromate = 46.0 mM

Therefore

Number of moles of sodium chromate present = (50 mL/1000)×46/1000 = 0.0023 M

Number of moles of copper (II) acetate present = 181.63 g/mol

number of moles of copper (II) acetate present = (0.708 g/181.63 g/mol) =0.0039 moles

Therefore 0.0039 moles of Cu(C₂H₃O₂)₂ × (2 moles of Na(C₂H₃O₂))/1 Cu(C₂H₃O₂)₂) = 0.00779 moles of Na(C₂H₃O₂)

also 0.0023 moles of Na₂CrO₄ × (2 moles of Na(C₂H₃O₂))/1 Na₂CrO₄) = 0.0046 moles of Na(C₂H₃O₂)

Therefore the Na₂CrO₄ is the limiting reactant and 0.0046 moles of Na(C₂H₃O₂) or acetate anion is formed

7 0
2 years ago
On another planet, the isotopes of titanium have the given natural abundances. Isotope Abundance Mass (amu) 46Ti 72.000% 45.9526
tiny-mole [99]

Answer:

46.784886 amu is the average atomic mass of titanium on that planet.

Explanation:

Fractional abundance of Ti-46 =72.000% = 0.72000

Atomic mass of Ti-46 = 45.95263 amu

Fractional abundance of Ti-48 =14.300% = 0.14300

Atomic mass of Ti-48 = 47.94795 amu

Fractional abundance of Ti-50 =13.700% = 0.13700

Atomic mass of Ti-50 = 49.94479 amu

\text{Average atomic mass }=\sum_{i=1}^n\text{(Fractional abundance)}_i\times \text{(Atomic mass of an isotopes})_i

Average atomic mass of titanium atom:

0.72000\times 45.95263 amu+0.14300\times 47.94795 amu+0.13700\times 49.94479 amu=46.784886 amu

46.784886 amu is the average atomic mass of titanium on that planet.

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