What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and
1 answer:
The name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
<h3>Nomenclature of Organic compounds</h3>From the question, we are to determine the name of the given molecule.
To name the compound, we will follow the IUPAC rules.
Some of IUPAC rules are
- Find the longest continuous carbon chain. Determine the root name for this parent chain.
- For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.
The given compound has 8 carbons and a double bond. The root name of the compound is octane.
By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.
Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.
Hence, the name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333
The diagram for the compound is attached below.
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Answer : The molarity of solution is, 1.73 mole/L
Explanation :
The relation between the molarity, molality and the density of the solution is,
where,
d = density of solution =
m = molality of solution = 2.41 mol/kg
M = molarity of solution = ?
= molar mass of solute (toluene) = 92 g/mole
Now put all the given values in the above formula, we get the molality of the solution.
Therefore, the molarity of solution is, 1.73 mole/L
Answer:
See explanation.
Explanation:
Hello!
In this case, we consider the questions:
a. Ideal gas at:
i. 273.15 K and 22.414 L.
ii. 500 K and 100 cm³.
b. Van der Waals gas at:
i. 273.15 K and 22.414 L.
ii. 500 K and 100 cm³.
Thus, we define the ideal gas equation and the van der Waals one as shown below:
Whereas b and a for hydrogen sulfide are 0.0434 L/mol and 4.484 L²*atm / mol² respectively, therefore, we proceed as follows:
a.
i. 273.15 K and 22.414 L.
ii. 500 K and 100 cm³ (0.1 L).
b.
i. 273.15 K and 22.414 L: in this case, v = 22.414 L / 1.00 mol = 22.414 L/mol
ii. 500 K and 100 cm³: in this case, v = 0.1 L / 1.00 mol = 0.100 L/mol
Whereas we can see a significant difference when the gas is at 500 K and occupy a volume of 0.100 L.
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