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What is the name for this molecule? a skeletal model of an 8-carbon zig zag chain. there is a double bond between the first and
1 answer:
The name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
<h3>Nomenclature of Organic compounds</h3>From the question, we are to determine the name of the given molecule.
To name the compound, we will follow the IUPAC rules.
Some of IUPAC rules are
- Find the longest continuous carbon chain. Determine the root name for this parent chain.
- For Alkenes (organic compounds with double bond), number the chain of carbons that includes the C=C so that the C=C has the lower position number. Change “ane” to “ene” and assign a position number to the first carbon of the C=C.
The given compound has 8 carbons and a double bond. The root name of the compound is octane.
By <u>IUPAC rules</u>, the compound is an <u>Octene</u>.
Since the double bond is between carbon-1 and carbon-2. The compound becomes 1-octene.
Hence, the name of the compound by using the <u>IUPAC nomenclature of organic compounds</u> is 1 -octene. The correct option is the last option - 1-octene.
Learn more on Nomenclature of Organic compounds here: brainly.com/question/26754333
The diagram for the compound is attached below.
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Answer : The percent yield is, 83.51 %
Solution : Given,
Mass of Zn = 5.00 g
Mass of = 25.00 g
Molar mass of Zn = 65.38 g/mole
Molar mass of = 168.97 g/mole
Molar mass of Ag = 107.87 g/mole
First we have to calculate the moles of Zn and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.1479 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 2 mole of
So, 0.1479 moles of react to give 0.1479 moles of
Now we have to calculate the mass of
Theoretical yield of = 15.95 g
Experimental yield of = 13.32 g
Now we have to calculate the percent yield.
Therefore, the percent yield is, 83.51 %