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3 years ago

Which list is in descending order?

Mathematics

2 answers:

Kaylis [27]3 years ago

8 0

Answer:

THE FIRST ONE

Step-by-step explanation:

im sure of it if not the go for b or d

Alja [10]3 years ago

6 0

The answer is B because if you convert all of them to decimals you get it in that order.

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in the equation 6x – 2 = –4x + 2, Spencer claims that the first step is to add 4x to both sides. Jeremiah claims that the first

trapecia [35]

Spencer would be the correct one because it's easier to keep your variables positive when trying to solve. Therefore, in order to keep the variable positive, one would have to add 4x to both sides.

4 0

3 years ago

Read 2 more answers

Determine the commutators of the operators a and a+,where a = (x + ip)/2 ^1/2 and a+ = (x - ip)/ 2 ^1/2

Vsevolod [243]

Answer:

Given that:

$a = (\frac{x+ip}{2})^{\frac{1}{2}}$ and $a+= (\frac{x-ip}{2})^{\frac{1}{2}}$

if a , a+ commutator, it obeys $aa^+ = a^+a$

First find:

$aa^+ = (\frac{x+ip}{2})^{\frac{1}{2}} (\frac{x-ip}{2})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

Now;

$a^+a =(\frac{x-ip}{2})^{\frac{1}{2}} (\frac{x+ip}{2})^{\frac{1}{2}} = (\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}$

= $(\frac{(x)^2-(ip)^2}{4})^{\frac{1}{2}}=(\frac{(x)^2+(p)^2}{4})^{\frac{1}{2}}$

therefore, $aa^+ = a^+a$ which implies the operators a and a+ are commutators.

7 0

3 years ago

The number 0.6064 represents the area under the standard normal curve below a particular z-score. What is the Z-score? Express t

Anastasy [175]

P(z < x) = 0.6064 - 0.5 = 0.1064

From the normal distribution table
P(z < 0.27) = 0.1064

Therefore the z-score is 0.27

I can't explain it very well for you, sorry.

4 0

3 years ago

Read 2 more answers

A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0

2 years ago

Lee can type 1 1/3 pages every 15 minutes. How many hours does it take him to type 10 2/3 pages

natta225 [31]

Answer:

2 hours

Step-by-step explanation:

if you can type 1 1/3 pages every 15 minutes than you can type 5 1/3 pages every hour. you divide 10 2/3 pages by how many pages Lee can type every hour and the result is 2 hours

8 0

3 years ago