First find the number of moles of KSCN is in 4.40g of KSCN
1. Number of moles = mass given (4.40g) / molecular weight(MW) (KSCN)
- to calculate MW, look for each element in the periodic table and add their atomic weight
2. Convert 200mL to liters
3. Concentration = number of moles/ volume in liters from (#2)
Answer:
209.68
Explanation:
The only number that is relevant (though the rest are quite interesting) is the last one 1.98 * 10^24
1 mole of Barium Acetate Contains 6.02*10^23 particles.
There are 4 moles of carbon to every mole of Barium Acetate.
1.98 * 10^24 atoms / (4*6.02*10^23)
0.8223 moles of Ba(C2H3O2)2
Ba = 137
4C = 4*12 48
6H = 6*1 6
4O = 4*16 64
1mole 255 grams
0.8223 * 255 = 209.68 grams
I have used rounded masses for these elements depending on the periodic table you use. Go through the question with your masses to get a more accurate answer. My answer will not differ by much. It is a guide.
<h3>
Answer:</h3>
1082.96 L
<h3>
Explanation:</h3>
We are given;
- Initial volume of helium gas, V1 = 793 L
- Initial temperature, T1 = 16.9°C
But, K = °C + 273.15
- Thus, initial temperature, T1 is 290.05 K
- Initial pressure, P1 = 759 mmHg
- New pressure at 4.05 km, P2 = 537 mmHg
- New temperature at 4.05 km, T2 = 7.1 °C
= 280.25 K
Assuming we are required to calculate the new volume at the height of 4.05 km
We are going to use the combined gas law.
- According to the combined gas law;
Therefore, the new volume of the balloon at the height of 4.05 km is 1082.96 L
PI3, but make sure it is a subscript of 3, not a large number.
You need to round to 3 significant digits.
0.783 g/ml
