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vladimir2022 [97]
3 years ago
10

PLS HELP I WILL MARK BRAINLYEST BUT PLS JUST HELP MEEEEEEEEEEEEEE

Chemistry
2 answers:
VLD [36.1K]3 years ago
8 0

Answer:

hi kirishima it is me 0412919

Explanation:

i will give u brainly :D

Irina-Kira [14]3 years ago
3 0

Answer:

Radio waves are electromagnetic waves within the frequencies 30KHz - 300GHz, and include microwaves. Microwaves are at the higher frequency end of the radio wave band and low frequency radio waves are at the lower frequency end.

Explanation:

hope this helps and i hope i can please get brainliest

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Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

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