If a race car is traveling South due to a 30N force and the parachute deploys resulting in a 10N force North what is the Net For
1 answer:
Answer:
F = 20 N south
Explanation:
It is given that,
Force applied on the racing car in south direction is 30 N and parachute deploys resulting in a 10 N force due North.
We need to find the net force on the car.
Let North denotes +y axis and South denotes -y axis.
So, F₁ = +10 N
F₂ = -30 N
Net force is :
It means that the net force is 20 N and it is acting in south. Hence (d) is correct.
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Answer:
<em>The power required by the pump is nearly 230.588 kW</em>
Explanation:
Flow rate of the pump Q = 1 m^3/s
the head flow H = 20 m
specific weight of water γ = 9800 N/m^3
efficiency of the pump η = 85%
First note that specific gravity of water is the product of the density of water and acceleration due to gravity.
γ = ρg
where ρ is density. For water its value is 1000 kg/m^3
g is the acceleration due to gravity = 9.81 m/s^2
The power to lift this water at this rate will be gotten from the equation
P = ρgQH
but ρg = γ
therefore,
P = γQH
imputing values, we'll have
P = 9800 x 1 x 20 = 196000 W
But the centrifugal pump that will be used will only be able to lift this amount of water after the efficiency factor has been considered. The power of pump needed must be greater than this power.
we can say that
196000 W is 85% of the power of the pump power needed, therefore
196000 = 85% of
where is the power of the pump needed
85% = 0.85
196000 = 0.85
= 196000/0.85 = 230588.24 W
<em>Pump power = 230.588 kW</em>