Question

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Need Help with this question ~

A man of mass 50 kg is pulling on a plank of mass 100kg kept on a smooth floor as shown with force of 100 N. If both man and plank move together find the force of friction acting on the man.


Picture is in attachment ~

Thanks for Answering !!​

Answer 1

Answer:

The man is standing on the plank then he is pulling the rope towards himself. He pushes forward with the legs so that pushes the plank "rope backwards

So that friction f acts in forward direction the plank.

The tension T in the rope is 100 N

$(A) \frac{100}{3} N \: towards \: left$

the fiction force f newtons.

$Man's \: F _{net} ⇒T−F=ma$

$F _{net} (man)⇒T−F=50a$

$Plank Fnet ⇒T+f=ma$

$F _{net} ( plank)⇒T+f=lov \: a$

$As T=100 N$

$a = \frac{4}{3} {m/s}^{2}$

$f = \frac{100}{3} \: newton$

Answer 2

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards.

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.

The man is standing on the plank. Then he is pulling the rope towards himself. He pushes the plank forward with the legs so that he can pull the rope backwards. So the friction f acts in the forward direction for the plank. Also f acts in the opposite direction on the man. The tension T in the rope is 100 N (given). Let the friction force = f Newtons.Let the common acceleration = a m/s^2

Man: net force = T - f = m a = 50 a

net force = T - f = m a = 50 a

Plank: net force = T + f = m a = 100 a

net force = T - f = m a = 50 a

Plank: net force = T + f = m a = 100 a

As T = 100 N, a = 4/3 m/s^2 and f = 100/3 Newtons.

[correct me if I'm wrong]:)