Answer:
![\frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
Step-by-step explanation:
Ok, let's do this step by step....
![\sqrt[3]{\frac{10x^{5} }{54x^{8} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10x%5E%7B5%7D%20%7D%7B54x%5E%7B8%7D%20%7D%20%7D)
Let's first simplify the x's:
![\sqrt[3]{\frac{10}{54x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B54x%5E%7B3%7D%20%7D%20%7D)
Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.
![\sqrt[3]{\frac{10}{2 * 27x^{3} } } = \sqrt[3]{\frac{5}{27x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B2%20%2A%2027x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B5%7D%7B27x%5E%7B3%7D%20%7D%20%7D)
Now, we can rewrite this as the following and solve the bottom part:
![\frac{\sqrt[3]{5} }{\sqrt[3]{27x^{3} } } = \frac{\sqrt[3]{5} }{3 \sqrt[3]{x^{3} } } = \frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B%5Csqrt%5B3%5D%7B27x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
The solution is
Answer: 18/7
Step-by-step explanation: random.
The answer is;
x(x+4)(x-4)=500
I don't know how it is, I just guess and it works
Answer:
none of them
Step-by-step explanation:
The area (A) of a triangle is calculated as
A = 0.5 × base × perpendicular height
Here the base is BC and perpendicular height is AD, hence
Area of ΔABC = 0.5 × BC × AD
The only way I can think of this is like...
c9 +4-7 = how many grams. so move 3 over then divide and simplify.
so 1/3 should be the amount you can eat
