4. In the figure below, a current of 2.8A flows
1 answer:
Answer:
The current flowing through the 4Ω resistor is;
C. 2.0 A
Explanation:
In the given figure, we have;
The series resistors in the bridge = 8Ω, and 4Ω are in series and 20Ω and 10Ω are in series
The sum of each of the series resistors are;
R₁ = 8Ω + 4Ω = 12Ω
R₂ = 20Ω + 10Ω = 30Ω
The equivalent resistors of the series resistors, R₁ and R₂ are parallel to each other
The current flowing through the 4Ω resistor = The current in R₁ = I₁
By the current divider rule, we have;
Therefore, I₁ = 2.0 A
The current flowing through the 4Ω resistor = I₁ = 2 A
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The cyclist accelerates from 0 m/s to 9 m/s in 3 seconds with an acceleration of 3 m/s².
Answer:
Explanation:
Acceleration exerted by an object is the measure of change in speed or velocity of that object with respect to time. So the initial and final velocities play a major role in determining the acceleration of the cyclist. As here the initial velocity of the cyclist is the speed at rest and that is given as 0 m/s. Then after 3 seconds, the velocity of the cyclist changes to 9 m/s.
Then acceleration = change in velocity/Time.
Acceleration = (9-0)/3=9/3=3 m/s².
So the cyclist accelerates from 0 m/s to 9 m/s in 3 seconds with an acceleration of 3 m/s².