A person has a mass of 42.0-kg. what is the persons weight on the moon?
1 answer:
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Answer:b
Explanation:
Given
mass of first cart
mass of second cart
velocity of first cart
conserving momentum
Initial kinetic Energy
Final Kinetic Energy
Ratio of initial Kinetic Energy to the Final Kinetic Energy
Answer:
The time taken is
Explanation:
From the question we are told that
The speed of first car is
The speed of second car is
The initial distance of separation is
The distance covered by first car is mathematically represented as
Here is the initial distance which is 0 m/s
and is the final distance covered which is evaluated as
So
The distance covered by second car is mathematically represented as
Here is the initial distance which is 119 m
and is the final distance covered which is evaluated as
Given that the two car are now in the same position we have that
Answer:
λ = 102.78 nm
This radiation is in the UV range,
Explanation:
Bohr's atomic model for the hydrogen atom states that the energy is
E = - 13.606 / n²
where 13.606 eV is the ground state energy and n is an integer
an atom transition is the jump of an electron from an initial state to a final state of lesser emergy
ΔE = 13.606 (1 / - 1 / n_{i}^{2})
the so-called Lyman series occurs when the final state nf = 1, so the second line occurs when ni = 3, let's calculate the energy of the emitted photon
DE = 13.606 (1/1 - 1/3²)
DE = 12.094 eV
let's reduce the energy to the SI system
DE = 12.094 eV (1.6 10⁻¹⁹ J / 1 ev) = 10.35 10⁻¹⁹ J
let's find the wavelength is this energy, let's use Planck's equation to find the frequency
E = h f
f = E / h
f = 19.35 10⁻¹⁹ / 6.63 10⁻³⁴
f = 2.9186 10¹⁵ Hz
now we can look up the wavelength
c = λ f
λ = c / f
λ = 3 10⁸ / 2.9186 10¹⁵
λ = 1.0278 10⁻⁷ m
let's reduce to nm
λ = 102.78 nm
This radiation is in the UV range, which occurs for wavelengths less than 400 nm.