Answer:
the work done by the linear spring will be equal to 23.04 k J
Explanation:
given,
k = 32 k N /m
deflected spring = 120 cm
= 1.2 m
work done by spring can be calculate as
= 
= 
= 23.04 k J
hence, the work done by the linear spring will be equal to 23.04 k J
Answer:
Explanation:
The complete detailed explanation which answer the question efficiently is shown in the attached files below.
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Answer:
The magnitude of the load can be computed because it is mandatory in order to produce the change in length ( elongation )
Explanation:
Yield strength = 275 Mpa
Tensile strength = 380 Mpa
elastic modulus = 103 GPa
The magnitude of the load can be computed because it is mandatory in order to produce the change in length ( elongation ) .
Given that the yield strength, elastic modulus and strain that is experienced by the test spectrum are given
strain = yield strength / elastic modulus
= 0.0027
You may have to do your research online for this.
