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marissa [1.9K]
3 years ago
6

10. True or False: You should select your mechanic before you experience vehicle failure.

Engineering
2 answers:
Naddika [18.5K]3 years ago
8 0
True ,

You’ve got to have knowledge first
ra1l [238]3 years ago
7 0

Answer:

True

Explanation:

Always see a professional if you have any issues that is not in your scope of practice

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How many meters per second is 100 meters and 10 seconds
Elden [556K]

Answer:

the velocity = 10 m / sec if an object moves 100 m in 10s

5 0
2 years ago
How long should the shafts remain in the furnace to achieve a desired centerline temperature of 800K? 2) Determine the temperatu
Phantasy [73]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

6 0
3 years ago
3. Technician A says passive permanent
Angelina_Jolie [31]

Answer:

Both technician A and B

Explanation:

Passive permanent  magnet ABS wheel speed sensors produce an  A/C voltage signal. Wheel speed sensors are a necessary ABS component and sensor input. It is used to inform the ABS control module of rotational wheel speed. A passive sensor creates an AC signal that changes frequency as the wheel changes speed. Moreover, input  from wheel speed sensors are used for anti- lock brake, electronic traction control, and  electronic stability control systems. Therefore, both technicians are correct.

6 0
3 years ago
Need help please????????!!!!!!
Alekssandra [29.7K]

Answer A the more traing the more you will know

Explanation:

4 0
3 years ago
If the specific surface energy for aluminum oxide is 0.90 J/m2 and its modulus of elasticity is (393 GPa), compute the critical
vampirchik [111]

Answer:

critical stress required for the propagation is 27.396615 ×10^{6} N/m²

Explanation:

given data

specific surface energy = 0.90 J/m²

modulus of elasticity E = 393 GPa = 393 ×10^{9} N/m²

internal crack length = 0.6 mm

to find out

critical stress required for the propagation

solution

we will apply here critical stress formula for propagation of internal crack

( σc ) = \sqrt{\frac{2E\gamma s}{\pi a}}    .....................1

here E is modulus of elasticity and γs is specific surface energy and a is half length of crack i.e 0.3 mm  = 0.3 ×10^{-3} m

so now put value in equation 1 we get

( σc ) = \sqrt{\frac{2E\gamma s}{\pi a}}

( σc ) = \sqrt{\frac{2*393*10^9*0.90}{\pi 0.3*10^{-3}}}

( σc ) = 27.396615 ×10^{6} N/m²

so critical stress required for the propagation is 27.396615 ×10^{6} N/m²

6 0
3 years ago
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