First we need to find the speed of the dolphin sound wave in the water. We can use the following relationship between frequency and wavelength of a wave:
where
v is the wave speed
its wavelength
f its frequency
Using
and
, we get
We know that the dolphin sound wave takes t=0.42 s to travel to the tuna and back to the dolphin. If we call L the distance between the tuna and the dolphin, the sound wave covers a distance of S=2 L in a time t=0.42 s, so we can write the basic relationship between space, time and velocity for a uniform motion as:
and since we know both v and t, we can find the distance L between the dolphin and the tuna:
Answer: 24.7 degrees Max
Explanation:
m*g = 3 * 9.8 = 29.4 N. = Wt. of book.
Fp = 29.4*sin A = Force parallel to the
plank.
Fn = 29.4*Cos A = Force perpendicular to
the plank.
Fs = u*Fn = 0.46*29.4*Cos A
Fp-Fs = m*a
29.4*sin A - 0.46*29.4*Cos A = m*0 = 0
29.4*Sin A = 0.46*29.4*Cos A
Sin A = 0.46*Cos A
Divide both sides by Cos A:
Sin A/Cos A = 0.46
Replace Sin A/Cos A with Tan A:
Tan A = 0.46
A = 24.7 degrees Max.
To solve the problem it is necessary to take into account the concepts related to frequency depending on the wavelength and the speed of light.
By definition we know that the frequency is equivalent to,
where,
c= Speed of light
While the wavelength is equal to,
Where,
L = Length
n = Number of antinodes/nodes
PART A) For the first part we have that our wavelength is 110MHz, therefore
Therefore the distance between the nodal planes is 1.36m
PART B) For this part we need to find the Length through the number of nodes (8) and the wavelength, that is,
Therefore the length of the cavity is 10.90m
2a) moment = 1.5P
2bi) 210*1 = 210Nm
2bii) 140N
2biii) 70 N
Answer:
Not between significant digits.
Explanation:
A zero not significant when it's not between significant digits.