1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm.calculate the stress developed in
the bar
1 answer:
Answer:25N/M^2
Explanation:
Force=20N Area=0.8M^2
Stress=force/area
Stress=20/0.8
Stress=25N/M^2
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