Resistivity of nichrome is high.
The additional charge transferred to the capacitors by the battery is 60 μC.
The increase in the total charge stored on the capacitors is 60 μC.
<u>Explanation</u>:
C = εоA / d
If the separation is halved, then the capacitance will be doubled and according to the equation q = CV, the charge will be doubled too.
- Initial charge of the capacitor is:
q = CV
= (6e - 6)
(10)
= 60 μC
Final charge of the capacitor:
q = (2C)V
= (2
6e - 6)
(10)
= 120 μC
additional charge transmitted is:
q' = 120 - 60
= 60 μC
= (C1 + C2) V
= (6 + 6)
(10)
= 120 μF
final total charge:
= (C1 + C2) V
= (2
6 + 6)
(10)
= 180 μF
Increase in the charge:
q' = 180 - 120
= 60 μC
Answer:
Electric force, F = 84.93 N
Explanation:
Given that,
Charge on particle 1, 
Charge on particle 1, 
The distance between charges, d = 8.09 cm
To find,
The magnitude of the force that one particle exerts on the other.
Solution,
The electric force of attraction or repulsion is given by the formula as:

k is the electrostatic constant

F = 84.93 N
So, the magnitude of the force that one particle exerts on the other is 84.93 N.