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frosja888 [35]
3 years ago
10

Two particles, one with charge − 7.97 μC −7.97 μC and one with charge 7.75 μC, 7.75 μC, are 8.09 cm 8.09 cm apart. What is the m

agnitude of the force that one particle exerts on the other?
Physics
2 answers:
mr Goodwill [35]3 years ago
4 0

Answer:

Electric force, F = 84.93 N

Explanation:

Given that,

Charge on particle 1, q_1=-7.97\ \mu C=-7.97\times 10^{-6}\ C

Charge on particle 1, q_2=7.75\ \mu C=7.75\times 10^{-6}\ C

The distance between charges, d = 8.09 cm

To find,

The magnitude of the force that one particle exerts on the other.

Solution,

The electric force of attraction or repulsion is given by the formula as:

F=\dfrac{kq_1q_2}{d^2}

k is the electrostatic constant

F=\dfrac{9\times 10^9\times 7.97\times 10^{-6}\times 7.75\times 10^{-6}}{(8.09\times 10^{-2})^2}

F = 84.93 N

So, the magnitude of the force that one particle exerts on the other is 84.93 N.

ZanzabumX [31]3 years ago
3 0

Answer:

84.9 N

Explanation:

q = 7.97 micro coulomb

q' = 7.75 micro coulomb

distance, d = 8.09 cm

The force between the two particles is given by

F=\frac{Kqq'}{r^{2}}

F=\frac{9\times 10^{9}\times 7.97\times 10^{-6}\times 7.75 \times 10^{-6}}{\left (8.09\times 10^{-2}  \right )^{2}}

F = 84.9 N

Thus, the force between the two charges is 84.9 N.

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Charles's law is best represent by the formula, V1T2= V2T1.

Charles's law state that for an ideal gas, at constant pressure, the absolute volume of a gas is directly proportional to the temperature.

that is

V α T

Or

V1T2= V2T1.

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How do fission nuclear reactions differ from fusion nuclear reactions? Fission reactions involve the conversion of matter into e
MakcuM [25]

How do fission nuclear reactions differ from fusion nuclear reactions?

A. Fission reactions involve the conversion of matter into energy, but fusion reactions do not. 

B. Fusion reactions involve the conversion of matter into energy, but fission reactions do not. 

C. Fission reactions are used to generate electricity for consumers, but fusion reactions are not. 

D. Fusion reactions are used to generate electricity for consumers, but fission reactions are not.

Answer:

C

Explanation:

Both fission and fusion are nuclear reactions that produce energy, but their applications differs.

 Fission is the splitting of a large (heavy, unstable) nucleus into smaller ones, and fusion is the process where nuclei of small atoms are combine together to form the nuclei of larger atoms releasing vast amounts of energy.

The correct answer is c. Fission reactions are used to generate electricity for consumers, but fusion reactions are not.

The physics of fusion is the process that makes the sun shine, and that makes the hydrogen bomb explode.

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The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-1
telo118 [61]
<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>

Explanation:

The half-life h of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this case, we are given the half life of two elements:

beryllium-13: h_{B-13}=5(10)^{-10}s=0.0000000005s

beryllium-15: h_{B-15}=2(10)^{-7}s=0.0000002s

As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?

We can find it out by the following expression:

h_{B-15}=X.h_{B-13}

Where X is the amount we want to find:

X=\frac{h_{B-15}}{h_{B-13}}

X=\frac{2(10)^{-7}s}{5(10)^{-10}s}

Finally:

X=400

Therefore:

The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.

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A model train engine was moving at a constant speed on a straight horizontal track. As the engine moved​ along, a marble was fir
bagirrra123 [75]

Answer:

The marble was moving in a projectile and the speed of the engine was 2.716 m/s

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The vertical component of the marble's flight path relative to the train

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of V m/s such that tan(61) = 4.9 / V

V = 4.9 / tan(61) = 2.716 m/s

This horizontal velocity component of the marble is the same as the

speed of the train i.e. 2.716 m/s.

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