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2 years ago

You get hit in the head with a baseball as it is falling. What are the action and reaction forces?

Physics

1 answer:

german2 years ago

5 0

Answer:

Action: Gravity pulls on the ball.

Reaction: The ball falls to the ground.

Explanation:

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A bicycle starts at 2.5m/s and accelerates along a straight path to a speed of 12.5m/s in a time of 4.5 seconds. What is the bic

zalisa [80]

Answer:

The bicyclist's acceleration is 2.2m/s^2

Explanation:

Given

$u = 2.5m/s$ ---- Initial Velocity

$v = 12.5m/s$ ---- Final Velocity

$t = 4.5s$ ---- Time

Required

Determine the acceleration

This will be solved using the first equation of motion

$v = u + at$

Substitute values for v, u and a

$12.5 = 2.5 + a * 4.5$

$12.5 = 2.5 + 4.5a$

Collect Like Terms

$4.5a = 12.5 - 2.5$

$4.5a = 10.0$

Solve for a

$a = 10.0/4.5$

$a = 2.2m/s^2$ ---- (approximated)

<em>Hence, the bicyclist's acceleration is 2.2m/s^2</em>

3 0

3 years ago

Acid rain is an example of which type of chemical weathering?

tino4ka555 [31]

The answer is Carbonic acid

6 0

3 years ago

Read 2 more answers

Which equation describes the line containing the points (-2, 3) and (1, 2)

snow_lady [41]

Answer:

$y = \frac{ - 1}{3}x + \frac{7}{3}$

Explanation:

$\frac{y - 3}{2 - 3} = \frac{x + 2}{1 + 2} \\ \ - y + 3 = \frac{x + 2}{3} \\ y = \frac{ - 1}{3}x + \frac{7}{3}$

8 0

3 years ago

Which object has the larger magnitude of its momentum?

Charra [1.4K]

The object that had the most 1000 ton weight has the most momentum

5 0

3 years ago

A physics professor is pushed up a ramp inclined upward at 30.0° above the horizontal as she sits in her desk chair, which slide

11111nata11111 [884]

Answer:

V = 3.17 m/s

Explanation:

Given

Mass of the professor m = 85.0 kg

Angle of the ramp θ = 30.0°

Length travelled L = 2.50 m

Force applied F = 600 N

Initial Speed u = 2.00 m/s

Solution

Work = Change in kinetic energy

$F_{net}d = \frac{1}{2}mv^{2} - \frac{1}{2}mu^{2}\\\frac{2F_{net}d }{m} = v^{2} -u^{2}\\ v^{2} =\frac{2F_{net}d }{m} +u^{2}\\ v^{2} =\frac{2(600cos30 - 85\times 9.8 \times sin30) \times 2.5 }{85} +2.00^{2}\\ v^{2} = 10.066\\v = 3..17m/s$

7 0

3 years ago